If 2 equations have the same y-intercept, they are overlapping, which means they have infinite solutions. So there is no way that 2 equations with the same y-intercept will have no solution. Thus your answer is: C)Never. 
        
                    
             
        
        
        
Hi! The temperature would be 18°.
There was a 4 hour period between 5 and 9 a.m.
So, I just took -10, and added 7 four times. 
-10 + 7 + 7 + 7 + 7 = 18
Hope this helps you! Happy thanksgiving, here's a turkey!
 
        
             
        
        
        
Answer:
Option A
Step-by-step explanation:
Given:
- a. 3x-5= 3x + 5
- b. 3x-5= 3x - 5
- c. 3x - 5 = 2x+5
- d. 3x-5 = 2x + 10
To find:
- Which one of the linear equations have no solution.
Solution:
 a)  3x-5= 3x + 5
Add 5 to both sides
 3x-5= 3x + 5 
3x - 5 + 5 = 3x + 5 + 5
Simplify 
(Add the numbers)
3x - 5 + 5 = 3x + 5 + 5
3x = 3x + 5 + 5
(Add the numbers)
3x  = 3x + 5 + 5
3x = 3x + 10
Subtract 3x from both sides
3x = 3x + 10
3x - 3x = 3x + 10 - 3
Simplify
(Combine like terms)
3x -3x = 3x + 10 - 3
0 = 3x + 10 - 3
(Combine like terms)
0 = 3x + 10 - 3
0 = 10
The input is a contradiction: it has no solutions
b)  3x-5= 3x - 5
 Since both sides equal, there are infinitely many solutions.
c)  3x - 5 = 2x+5
Add 5 to both sides
3x = 2x + 5 + 5
Simplify  2x + 5 + 5 to 2x + 10
3x = 2x + 10
Subtract 2x from both sides
3x - 2x = 10
Simplify 3x - 2x to x.
x = 10
d) 3x-5 = 2x + 10
Add 5 to both sides
3x = 2x + 10 + 5
Simplify 2x + 10 + 5 to 2x + 15
3x = 2x + 15
Subtract 2x from both sides
3x - 2x = 15
Simplify 3x -2x to x.
x = 15
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Answer:
As you can see all c and d both have solutions, eliminating them as options. Option B has infinite solutions leaving Option A which has no solutions.
Therefore, <u><em>Option A</em></u> is the linear equation that has no solution.
 
        
                    
             
        
        
        
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
        
             
        
        
        
Answer: Shortest side = 6 inches, Medium side = 10 inches and Longest side = 11 inches 
Step-by-step explanation: The perimeter has been given as 27 inches, and we know that the perimeter of any given figure is the addition of all sides. The sides are unknown yet, but we have clues as follows;
The longest side is 5 inches longer than the shortest side, hence the longest side equals s + 5. The medium side is 4 inches longer than the shortest side, hence the medium side equals s+ 4. Th shortest side remains s.
Therefore with the perimeter given as 27, we now have the expression;
s + s + 4 + s + 5 = 27
3s + 9 = 27
Subtract 9 from both sides of the equation 
3s = 18
Divide both sides of the equation by 3
s = 6
Hence, the sides of the triangle are given as 6, (6+ 4) and (6+ 5), which is,
6 inches, 10 inches and 11 inches.