Answer:
No, it will not pop. (See photo)
Explanation:
Answer:
Δ should be 0.1009
Explanation:
The change in the units volume when temperature change can be expressed as:
∆v = v0Δ
with v0 = the initial volume
with = the volumetric temperature expansion coefficient
with Δ = the change of temperature.
To calculate the final volume vf we'll get:
v = v0 + ∆ = v0(1 + Δ)
The liquid just begins to spill out if v(benzene) = :
v()(1 + Δ) = = v() (1 + Δ)
(v(cavity)-v(benzene))/(((benzene) -(copper)) = Δ
((1.22*10^-3)-(1.1*10^-3))/((1240*10^-6)-(51*10^-6)) = Δ
Δ = 0.1009
Δ should be 0.1009
Answer:
pH =6.70
Explanation:
When Kw = 1x10^-14
[H3O+] = [OH-] --> 1x10-7
Kw =3.98x^10-14
3.98x^10-14 = [H3O+] . [OH-]
√ (3.98x^10-14) = [H3O+] = [OH-]
[H3O+] = 1.99×10^-7
- log [H3O+] = pH ---> -log 1.99x10^-7 = 6.70
Answer:
This happens because a metal is less reactive than carbon and it can be extracted from its oxides by heating with carbon. The carbon displaces metal from the compound and removes the oxygen from the oxide.
Noble gasses have full outer shells giving them 8 electrons
