Answer:
The final temperature is:- 7428571463.57 °C
Explanation:
The expression for the calculation of heat is shown below as:-
Where,
is the heat absorbed/released
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)
Specific heat of water = 4.18 J/g°C
Initial temperature = 35 °C
Final temperature = x °C
![\Delta T=(x-35)\ ^0C/tex] Q = [tex]1.3\times 10^4](https://tex.z-dn.net/?f=%5CDelta%20T%3D%28x-35%29%5C%20%5E0C%2Ftex%5D%0A%3C%2Fp%3E%3Cp%3EQ%20%3D%20%5Btex%5D1.3%5Ctimes%2010%5E4)
kcal
Also, 1 kcal = 4.18 kJ = 
J
So, Q = 
J = 54340000 J
So,
Thus, the final temperature is:- 7428571463.57 °C
Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen , 
.
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon , 
.
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .
Answer:
They are eukaryotic, which means they have a nucleus. Most have mitochondria
