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Lady bird [3.3K]
3 years ago
7

Bob roller skates with a constant speed of 8 km/h. How long will he take to 2 poin

Chemistry
1 answer:
Jet001 [13]3 years ago
6 0

Answer: 1.25 hours (75 minutes)

Explanation: 1 hour / 8 km • (10 km) = 1.25 hours

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If a substance contains a hydrogen ion concentration of 1.0 x 10-5 M, which types of ions does it contain more of?
miss Akunina [59]

Since the pH of the substance is 5, the substance contains more of hydrogen ions.

<h3>What is pH of a solution?</h3>

The pH of a a solution is the negative logarithm to base ten of the hydrogen ions concentration of the solution.

pH = -log[H^{+}]

A neural solution has pH 7.

A solution with pH below 7 has more hydrogen ions while a solution with pH above 7 has more hydroxide ions.

The pH of a substance contains a hydrogen ion concentration of 1.0 x 10-5 M is 5.

Therefore, the substance contains more of hydrogen ions.

Learn more about pH at: brainly.com/question/940314

6 0
2 years ago
What is the main intermolecular force in H2CO?
aivan3 [116]
Dipole-dipole interactions, and London dispersion interactions
5 0
4 years ago
HELP ME PLEASE WILL GIVE BRAINLIEST
Natasha2012 [34]

Answer:

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Explanation:

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4 0
3 years ago
Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th
Vera_Pavlovna [14]

Answer:

[H^+]=0.000285

pH=3.55

Explanation:

In this, we can with the <u>ionization equation</u> for the hydrazoic acid (HN_3). So:

HN_3~~H^+~+~N_3^-

Now, due to the Ka constant value, we have to use the whole equilibrium because this <u>is not a strong acid</u>. So, we have to write the <u>Ka expression</u>:

Ka=\frac{[H^+][N_3^-]}{[HN_3]}

For each mol of H^+ produced we will have 1 mol of N_3^-. So, we can use <u>"X" for the unknown</u> values and replace in the Ka equation:

Ka=\frac{X*X}{[HN_3]}

Additionally, we have to keep in mind that HN_3 is a reagent, this means that we will be <u>consumed</u>. We dont know how much acid would be consumed but we can express a<u> subtraction from the initial value</u>, so:

Ka=\frac{X*X}{0.004-X}

Finally, we can put the ka value and <u>solve for "X"</u>:

2.2X10^-^5=\frac{X*X}{0.004-X}

2.2X10^-^5=\frac{X^2}{0.004-X}

X= 0.000285

So, we have a concentration of 0.000285 for H^+. With this in mind, we can calculate the <u>pH value</u>:

pH=-Log[H^+]=-Log[0.000285]=3.55

I hope it helps!

8 0
3 years ago
With some value of mixture CO and O2 density by Hydrogen is 15 . When reaction begun some time later density by Hydrogen of the
quester [9]
For every 2 moles of CO and 1 mole of O2, 2 moles of CO2 will be produced.

The ratio is 2:1:2.

Hope this helps! :)
7 0
3 years ago
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