Answer:
The answer is 1.06g.
Explanation:
Analysis of question:
1. Identify the information in the question given.
- volume of HCl is 2 dm3
- pH of HCl is 2.0
2. What the question want?
- mass of Na2CO3 is ?(unknown)
- 3. Do calculation.
- 1st-Write a balanced chemical equation:
Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2
- 2nd-Determine the molarity of HCl with the value of 2.0.
pH= -log[H+]
2.0= -log[H+]
log[H+]= -2.0
[H+]= 10 to the power of negative 2(10-2)
=0.01 mol dm-3
molarity of HCl is 0.01 mol dm-3
- 3rd-Find the number of moles of HCl
n=MV
=0.01 mol dm-3 × 2 dm3
=0.02 mol of HCl
- 4th-Find the second mol of it.
Based on the chemical equation,
2.0 mol of HCl reacts with 1.0 mol of Na2CO3
0.02 mol of HCl reacts with 0.01 mol of Na2CO3
<u>N</u><u>a</u>2CO3>a=<u>1</u><u> </u>mol
<u>2</u><u>H</u>Cl>b=<u>2</u><u> </u>mol
mass= number of mole × molar mass
g=0.01 × [2(23)+ 12+ 3(16)]
g=0.01 × 106
# =1.06 g.
The percent of histidine side chains would be deprotonated at pH 7.5 is 5.77 %.
<h3>What is pKa?</h3>
The term pKa refers to the negative logarithm of the acid dissociation constant (Ka). The pH is the negative logarithm of the hydrogen ion concentration.
Hence;
Ka = Antilog (-6) =
[H^+] = Antilog (-7.5) = 
We now have to use the formula;
α = ![\sqrt{} \frac{Ka}{[H^+] }](https://tex.z-dn.net/?f=%5Csqrt%7B%7D%20%5Cfrac%7BKa%7D%7B%5BH%5E%2B%5D%20%7D)
α = 
α = 5.77 %
Hence, the percent of histidine side chains would be deprotonated at pH 7.5 is 5.77 %.
Learn more about percent dissociation: brainly.com/question/12273293
(3) loses one electron and becomes positively charged
Lithium has one valence electron and Bromine has seven. Therefore Lithium will give up its one to Bromine for both to have an octet
A is correct vegetables cannot be like acids or alkaline because they foods
