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LenKa [72]
3 years ago
9

A spark is generated in an automobile spark plug when there is an electric potential of 3000 V across the electrode gap. If 60 W

of power is generated in a single spark that delivers a total charge of 3 nC, how long does it take for the spark to travel across the gap?
A. 50 ns
B. 75 ns
C. 125 ns
D. 150 ns
E. 225 ns 5
Physics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

The correct option is  d

Explanation:

From the question we are told that

     The  electric potential is  V  =  3000 \ V

      The  power is  P  =  60 \ W

      The  charge delivered is  q = 3nC  =  3.0 *10^{-9} \ C

Generally the power generated is mathematically represented as

         P  =  I V

=>      I  =  \frac{P}{V }

=>       I  =  \frac{60 }{3000 }

=>     I  =  0.02 \ A

This  current flow is mathematically represented as

           I  =  \frac{q -q_o}{\Delta t }

Where q_o is the charge delivered at t=0 s which is 0s

     So

             0.02 =  \frac{ (3.0 *10^{-9}) -0 }{t - 0 }

               t =  1.50 *10^{-7 } \ s

               t =  150 *10^{-9 } \ s

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Answer:

1.4007\times 10^{-8}\ N

1.50075\times 10^{-6}\ N

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Explanation:

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Gravitational force of attraction is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 70\times 3}{1^2}\\\Rightarrow F=1.4007\times 10^{-8}\ N

The force between baby and obstetrician is 1.4007\times 10^{-8}\ N

F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(6\times 10^{11})^2}\\\Rightarrow F=1.50075\times 10^{-6}\ N

The force between the baby and Jupiter is 1.50075\times 10^{-6}\ N

F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(9\times 10^{11})^2}\\\Rightarrow F=0.000000667\ N

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A copper wire of diameter 0.80 mm fails at an engineering stress = 248.2 MPa. Its ductility is measured as 75% reduction of area
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Answer:

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A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g,
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The radius of each jawbreaker is approximately 0.68 cm.

<h3>Volume of a sphere;</h3>
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where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

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volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

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Answer:

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If I were to put my process into steps:

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*This all seems to line up perfectly, but do let me know if my answer doesn't match up with what you might find to he the answer later on.

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