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3 years ago

50 point!! Will mark brainliest!! (Please help)

Physics

2 answers:

wariber [46]3 years ago

5 0

I agree with the other answer

What is the variable?

~the price is the variable.

What happens to demand?

~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.

jok3333 [9.3K]3 years ago

4 0

What is the variable?

~the price is the variable.

What happens to demand?

~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.

Hope this helps- have a good day bro cya)

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A skateboarder is moving at 1.75 m/s when she starts going up an incline that causes an acceleration of -0.20 m/s2

Rudiy27

Answer:

Approximately $7.66\; \rm m$ .

Explanation:

<h3>Solve this question with a speed-time plot</h3>

The skateboarder started with an initial speed of $u = 1.75\; \rm m \cdot s^{-1}$ and came to a stop when her speed became $v = 0\; \rm m \cdot s^{-1}$ . How much time would that take if her acceleration is $a = -0.20\; \rm m \cdot s^{-1}$ ?

$\begin{aligned} t &= \frac{v - u}{a} \\ &= \frac{0\; \rm m \cdot s^{-1} - 1.75\; \rm m \cdot s^{-1}}{-0.20\; \rm m \cdot s^{-2}} \approx 8.75\; \rm s\end{aligned}$ .

Refer to the speed-time graph in the diagram attached. This diagram shows the velocity-time plot of this skateboarder between the time she reached the incline and the time when she came to a stop. This plot, along with the vertical speed axis and the horizontal time axis, form a triangle. The area of this triangle should be equal to the distance that the skateboarder travelled while she was moving up this incline until she came to a stop. For this particular question, that area is approximately equal to:

$\displaystyle \frac{1}{2} \times 1.75\; \rm m \cdot s^{-1} \times 8.75\; \rm s \approx 7.66\; \rm m$ .

In other words, the skateboarder travelled $15.3\; \rm m$ up the slope until she came to a stop.

<h3>Solve this question with an SUVAT equation</h3>

A more general equation for this kind of motion is:

$\displaystyle x = \frac{1}{2}\, (u + v) \, t = \frac{1}{2}\, (u + v)\cdot \frac{v - u}{a}= \frac{v^2 - u^2}{2\, a}$ ,

where:

$u$ and $v$ are the initial and final velocity of the object,
$a$ is the constant acceleration that changed the velocity of this object from $u$ to $v$ , and
$x$ is the distance that this object travelled while its velocity changed from $u$ to $v$ .

For the skateboarder in this question:

$\begin{aligned}x &= \frac{v^2 - u^2}{2\, a}\\ &= \frac{\left(0\; \rm m \cdot s^{-1}\right)^2 - \left(1.75\; \rm m \cdot s^{-1}\right)^2}{2\times \left(-0.20\; \rm m \cdot s^{-2}\right)}\approx 7.66\; \rm m \end{aligned}$ .

6 0

4 years ago

A hydrogen atom has a radius of 2.5 x 10-11 m Determine the radius of a magnesium atom.

baherus [9]

Answer:

$R = 1.5* 10^{-10}m$

Explanation:

Given

$r = 2.5 * 10^{-11}m$ -- radius of hydrogen atom

See attachment

Required

Determine the radius of magnesium atom (R)

From the attachment, the ratio of a hydrogen atom to a magnesium atom is:

$Ratio = 6mm : 36mm$

Simplify

$Ratio =1 : 6$

Represent the radius as ratio:

$Ratio = r : R$

Substitute $r = 2.5 * 10^{-11}m$

$Ratio = 2.5 * 10^{-11}m : R$

Equate both ratios

$2.5 * 10^{-11}m : R = 1 : 6$

Express as fraction

$\frac{2.5 * 10^{-11}m}{R} = \frac{1}{6}$

Cross Multiply

$R * 1 = 2.5 * 10^{-11}m * 6$

$R * 1 = 2.5 * 6* 10^{-11}m$

$R * 1 = 15* 10^{-11}m$

$R = 15* 10^{-11}m$

$R = 1.5*10* 10^{-11}m$

$R = 1.5* 10^{1-11}m$

$R = 1.5* 10^{-10}m$

Hence, the radius of the magnesium atom is: $1.5* 10^{-10}m$

6 0

3 years ago

Does anyone know the answer to all of these questions

Rasek [7]

Answer:

i don't understand the hw

5 0

3 years ago

1. Spring force is proportional to stretch distance, F=kd. Do you expect doubling the stretch distance double the force?

Solnce55 [7]

Answer:

Yes

Explanation:

The spring force is given as:

F = kd

F is the spring force

K is the spring constant

d is the magnitude of the stretch

Since k is a constant, therefore, doubling the stretch distance will double the force.

Both stretch distance and force applied can be said to be directly proportional to one another.

3 0

3 years ago

quzilet The Magnet Recognition Program for health care organizations is based on fourteen forces of magnetism related to five ma

Lena [83]

Answer:

4. Personnel policies and programs

Explanation:

The Health care organizations that apply for Magnet status must demonstrate new ways of doing things and innovations in professional practice.

Personnel policies and programs is one of the forces of magnetism that impacts the structural empowerment of the organization.

The Personnel policies of an organization should provide an innovative environment in which the staff are developed and empowered. Empirical quality outcomes are reviewed by assessing the quality of care. New knowledge, innovations, and improvements are reviewed by assessing the quality improvement of the health care organization. Interdisciplinary relationships are assessed to review exemplary professional practice.

6 0

3 years ago