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Nana76 [90]
3 years ago
12

Assessing how well one variable predicts another variable is to blank as detecting cause-effect relationships between different

variables is to
Physics
2 answers:
Reptile [31]3 years ago
7 0
Are you asking about independent and dependent variables?
hammer [34]3 years ago
3 0

Answer:

D) correlational research; experimental research

Explanation:

In correlational research the effect that one variable has on the other is studied without the addition of any external factor by the researcher. The subject is studied in a natural environment.

In experimental research how and why one variable affects another variable is studied. The subject is studied in the presence of various different variables introduced by the researcher.

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Suppose you pull two opposite sides of the loop away from each other, such that the other two sides get closer, reducing the loo
HACTEHA [7]

Answer:

Explanation:

Magnetic field is oriented downwards . area of loop is decreasing so downward flux is decreasing . To increase the downward flux , current induced will be clockwise so that flux generated by induced current increases the downwards flux . It is in accordance with Len'z law.

6 0
3 years ago
What quantities belong in cells X and Y?
satela [25.4K]

Answer:

X: period

Y: tangential speed

Explanation:

100% on quiz your welcome(:

6 0
2 years ago
In a standard tensile test, a steel rod of 7 8-in. diameter is subjected to a tension force of 17 kips. Knowing that ν = 0.30 an
natali 33 [55]

Answer:

(a) Elongation of the rod==5.61×10⁻⁹m

(b) Change in diameter=1.640×10⁻⁸m

Explanation:

Given data

Diameter d=78 in=1.9812 m

Cross Area is:

A=(\pi /4)d^{2} \\A=(\pi /4)(1.9812m)^{2}\\A=3.08m^{2}

Applied Load P=17 KN=17×10³N

E=29 × 106 psi=1.99947961×10¹¹Pa

Stress and Strain in x direction

Stress in x direction

σ=P/A

=\frac{17*10^{3}N }{3.08m^{2} }\\ =5517.25Pa

σ=5517.25 Pa

Strain in x direction

ε=σ/E

=\frac{5517.25}{1.99947961*10^{11} } \\=2.76*10^{-8}

ε=2.76×10⁻⁸

Part (a)

Elongation of the rod=Lε

=(0.2032)(2.76×10⁻⁸)

Elongation of the rod==5.61×10⁻⁹m

Part(b) Change in diameter

Strain in y direction

ε₁= -vε

ε₁= -(0.30)(2.76×10⁻⁸)

ε₁=-8.28×10⁻⁹

Change in diameter=d×ε₁

Change in diameter=(1.9812m)×(-8.28×10⁻⁹)

Change in diameter=1.640×10⁻⁸m

4 0
3 years ago
While bats emit a wide variety of sounds, one type emits pulses of sound at a frequency between 39 kHz and 78 kHz. What is the r
sdas [7]

Answer:

The range of wavelengths of the sound is 7692.30 m and 3846.15 m

Explanation:

A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.

Bat uses ultrasonic waves. It moves with the speed of light.

If f = 39 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{39\times 10^3}\\\\\lambda=7692.30\ m

If f = 78 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{78\times 10^3}\\\\\lambda=3846.15\ m

So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.

6 0
3 years ago
1. the most suitable cutting process to use on ferrous metals such as straight carbon steel is
dangina [55]

Answer:

plasma arc

cutting

Explanation:

It is plasma arc cutting because i think it is

6 0
3 years ago
Read 2 more answers
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