Given:
Water, 1.5kg at boiling point
Required:
Heat required to vaporize at boiling
point
Solution:
Water at boiling point is at
100degrees Celsius
Changing it into Kelvin, just dd
273 to 100 = 373 K
H
= mCpT
H
= (1.5kg)(4.184kJ/kg-K)(373K)
<span>H =
2340.9kJ</span>
Answer:
If I am correct, the answer is D. Law of conservation of energy
Explanation:
the potential energy "converts" to kinetic once Luke is in motion.
Answer:
B.useful products
Explanation:
industry is a sector that produces goods or services within an economy
Answer:
Option 10. 169.118 J/KgºC
Explanation:
From the question given above, the following data were obtained:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1.61 KJ
Mass of metal bar = 476 g
Specific heat capacity (C) of metal bar =?
Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:
1 kJ = 1000 J
Therefore,
1.61 KJ = 1.61 KJ × 1000 J / 1 kJ
1.61 KJ = 1610 J
Next, we shall convert 476 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
476 g = 476 g × 1 Kg / 1000 g
476 g = 0.476 Kg
Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1610 J
Mass of metal bar = 0.476 Kg
Specific heat capacity (C) of metal bar =?
Q = MCΔT
1610 = 0.476 × C × 20
1610 = 9.52 × C
Divide both side by 9.52
C = 1610 / 9.52
C = 169.118 J/KgºC
Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC
Hahahahha ok it’s B or C or it B
