The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Given parameters.
- Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
- The current i = 9.00 A in the positive direction of the z axis.
- The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T
To find.
The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.
F = i L x B
Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.
The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.
Let's calculate.
F = 2.5 (0.985 i ^ - 0.242 j ^)
F = ( 2.46 i ^ - 0.605 j^ ) N
To find the magnitude we use the Pythagorean theorem.
F =
F =
F = 2.53 N
Let's use trigonometry for the direction.
Tan θ ’=
θ'= tan⁻¹
θ'= tan⁻¹1 ( )
θ’= -13.8º
To measure this angle from the positive side of the x-axis counterclockwise.
θ = 360- θ'
θ = 360 - 13.8
θ = 346.2º
In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Learn more here: brainly.com/question/2630590
The most fundamental property of a star that determines its evolution is the MASS of the star.
In fact, while low-mass stars usually end their life becoming red giants and then white or black dwarfs, the high-mass stars can evolve into red supergiants and eventually originate a supernova. After the explosion of the supernova, depending on their mass, they can becomes neutron stars or collapse into black holes.
<span>The force that opposes the movement of an object through water is called drag. This is a type of frictional force. This force normally depends on the density and the viscosity of the fluid in question. The liquid which has more density and more viscosity or stickiness will produce a greater amount of drag force on an object than a fluid that is less dense and less viscous in nature. River water normally has less drag than that of sea water. </span><span> <span>
</span></span>
<h2>
Distance traveled in 1 second after drop is 4.9 m</h2><h2>
Distance traveled in 4 seconds after drop is 78.4 m</h2>
Explanation:
We have s = ut + 0.5at²
For a free falling object initial velocity u = 0 m/s and acceleration due to gravity, g = 9.8 m/s²
Substituting
s = 0 x t + 0.5 x 9.8 x t²
s = 4.9t²
We need to find distance traveled in 1 s and 4 s
Distance traveled in 1 second
s = 4.9 x 1² = 4.9 m
Distance traveled in 4 seconds
s = 4.9 x 4² = 78.4 m
Distance traveled in 1 second after drop = 4.9 m
Distance traveled in 4 seconds after drop = 78.4 m
D.very small amounts of mass.