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2 years ago

Predict the following products balance determine reaction

Chemistry

1 answer:

Nady [450]2 years ago

4 0

1) CuCl2+H2S—>CuS+2HCl
Double replacement

2)ZnCO3—>ZnO+CO2 (already balanced)
Decomposition

3)2Zn+2HCl—>2ZnCl+H2
Single replacement

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1.2 g of sucrose is added to water with the final volume of 75 ml. What is the concentration of sucrose in %w/v?

Firlakuza [10]

Answer:

16 g/L

Explanation:

Given that:-

Mass of sucrose added = 1.2 g

Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )

%w/v is defined as the mass of the solution in 1 L of the solution.

So,

$\%\ w/v=\frac{Mass_{solute}}{Volume_{Solution}}$

$\%\ w/v=\frac{1.2\ g}{0.075\ L}=16\ g/L$

8 0

3 years ago

Which one is correct

Ksju [112]

The answer is C, because wind turbines are used to produce electricity, and it's also the most safest way--but they are expensive.

3 0

3 years ago

Read 2 more answers

If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?

Lorico [155]

Answer:

Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3

Explanation:

Not much of one

4 0

1 year ago

Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles O2 to the

jek_recluse [69]

Answer:

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Explanation:

Step 1: Data given

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate the mol ratio

For 3 moles O2 we'll have 4 moles Fe

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Option b says we have 2 mole Fe2O3 for each 4 moles Fe

This doesnt say anything about O2. So doesn't apply for this question.

Option C says we have 4 moles of Fe for each 2 moles Fe2O3

This is the same as option B, so doesn't apply for this question.

Option D says for each 3 moles of O2 we have 2 Fe2O3

This is true, but doesn't say anything about Fe so doesn't apply here.

4 0

3 years ago

Read 2 more answers

A steel beam that is 7.00 m long weighs 326 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending

GrogVix [38]

Answer:

The answer to the question is

Suki is 1.12 m close to the end of the steel beam before the beam begins to tip

Explanation:

To solve the question we list out the known variables first

Length of steel beam, L = 7.00 m

Weight of steal beam W = 326 N

Distance between supports = 3.00 m

Weight of Suki = 555 N

By moments theory, the sum of moments about a point = 0

and assuming the steal beam is uniform, the weight of the beam will act at the center of the beam

As described the supports are 2.00 m from each end of the beam thus

taking moments about one of the support with Suki between the end of the beam and the support we have

Distance from center of beam to support = 1.5 m

Distance of Suki to the nearest support = x m

therefore 555 × x + 326 × 1.5 = 0

or x = -0.881 m on the other side of the support

Therefore Suki is (2 - 0.881) m or 1.12 m close to the end before the beam begins to tip

7 0

3 years ago