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Aleksandr-060686 [28]
2 years ago
14

An oceanographer went into the ocean to measure the salinity at different areas. Where would you expect the oceanographer to fin

d the highest salinity?
Hurry!
Chemistry
1 answer:
grigory [225]2 years ago
8 0

Due to high evaporation rate and low precipitation, the oceanographer to find the highest salinity at the tropics.

<h3>What is salinity?</h3>

Salinity refers to the salt content of a water body such as rivers and oceans.

Oceans and seas have high salinity due to the presence of many dissolved minerals.

Different area of the oceans have different salinities.

Salinity is highest at the tropics and equator due to high rate of evaporation and low precipitation.

Therefore, the oceanographer to find the highest salinityat the tropics.

Learn more about salinity at: brainly.com/question/20283396

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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
forsale [732]
Doesnt the number of carbon atoms stay the same.
Though the weight of carbon in 1.5g is 1.24g.

This is because the RAM of C4 is 48.

The RFM of C4H10 is 58. Therefore, 48/58 is carbon in butane.

48/58 x 1.5 = 1.24g
7 0
3 years ago
Is a faded picture a chemical or physical change?
nalin [4]
It is a chemical change
5 0
3 years ago
Read 2 more answers
A fat is composed of long chains of carbon and hydrogen atoms. In a reaction with a strong base, a fat forms a soap and glycerol
Nonamiya [84]

Answer:

Empirical formula is C₉H₁₅O

Molecular formula = C₈₁H₁₃₅O ₉

Explanation:

Percentage of carbon = 77.60%

Percentage of oxygen = 11.45%

Percentage of hydrogen = 10.95%

Molecular weight = 1253 g/mol

Molecular formula = ?

Empirical formula = ?

Solution:

Number of gram atoms of C = 77.60 g /12g/mol =6.5

Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72

Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9

Atomic ratio:

C               :            H                 :    O

6.5/0.72   :       10.9/0.72         :   0.72/0.72

     9          :            15              :         1

C : H : O = 9 : 15 : 1

Empirical formula is C₉H₁₅O

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 1253 / 139

n = 9

Molecular formula = n (empirical formula)

Molecular formula = 9 (C₉H₁₅O )

Molecular formula = C₈₁H₁₃₅O ₉

4 0
4 years ago
Which of the following compounds will not possess dipole dipole interactions between its molecules?A. HBr.B. CO2.C. PH.D. NO.E.
Black_prince [1.1K]

Answer:

B. CO2

Explanation:

Because its a neutral compound hence lacks any form of dipole dipole interaction

6 0
4 years ago
She dissolves a 10.0mg sample in enough water to make 30.0mL of solution. The osmotic pressure of the solution is 0.340torr at 2
uranmaximum [27]

Answer:

(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

(b)The freezing point for the aqueous solution is -3.413\times10^{-5} C

Explanation:

The osmotic pressure (π) is given by the following equation:

\pi =cRT

c= Concentration of solution

R = universal gas constant = 62.364 \frac{L\times torr}{mol\times K}

T = temperature

Weight of solute = w = 10.0 mg

Let the molecular weight of the solute be m g/mol.

Concentration = c=\frac{n}{V}\\ n=\frac{w}{m}\\ n=\frac{10\times10^{-3}}{m}\\c=\frac{10\times10^{-3}}{m\times30\times10^{-3}}M

m=\frac{RT}{3\pi}

m = 18220.071g/mol

Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

\Delta T_{f}=K_{f}m

m is the molality of the solution.

m = 1.835\times10^{-5} mol/kg

\Delta T_{f}=1.86\times m

\Delta T_{f} = 3.413\times10^{-5} C

The freezing point for the aqueous solution is -3.413\times10^{-5} C

8 0
3 years ago
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