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Scorpion4ik [409]
2 years ago
13

Given that x =6 and Y = -4 evaluate each of the following expressions2x^2 - y^3

Mathematics
2 answers:
Taya2010 [7]2 years ago
8 0

Answer:

See below.

Step-by-step explanation:

2(6)^2-(-4)^3

2(36)+64

72+64

136

-hope it helps

tester [92]2 years ago
6 0

Answer:

136

Step-by-step explanation:

2(6)^2-(-4)^3

2(36)+64

72+64

-Hope it helps :)

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A calculator costs $d. A school buys 90 calculators, and gets a $100 discount for bulk purchasing. How much did the school spend
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Step-by-step explanation:

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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

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Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

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