Answer:
The molarity of the solution is 1,03 M.
Explanation:
Molarity is a concentration measure that expresses the moles of solute (in this case HBR) in 1 liter of solution (1000ml). First we calculate the mass of 1 mol of HBr, to calculate the moles that are in 50 g of said compound:
Weight 1 mol HBr= Weight H + Weight Br= 1,01g + 79,90g= 80, 91 g/mol
80,91 g ----1 mol HBr
50,0 g------x= (50,0 g x1 mol HBr)/80,91 g= 0,62 mol HBr
600 ml solution-----0,62 mol HBr
1000ml solution------x= (1000ml solution x 0,62 mol HBr)/600 ml solution
<em>x=1,03 moles HBr ---> The solution is 1,03M</em>
Well you are at a 86% so t<span>his is considered a "B" grade on an average grade scale. If you take 50 points we would need to know the Total point you could have got in that class to be able to see how much a percent was the assignment work and then take that percentage of the assignment and subtract it from the 86% to see where on the scale you would fall in after the assignment points were taken off. Hope this helps :)
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