Answer:
3.60 ml
Explanation:
First of all we must put down the equation of the reaction. This will serve as a guide to our solution;
KOH(aq) + HBr(aq) -----> KBr(aq) + H2O(l)
The following were given in the question;
Concentration of acid CA= 2M
Volume of acid VA= 18ml
Concentration of base CB= 0.01 M
Volume of base VB= ????
Number of moles of acid NA= 1
Number of moles of base NB= 1
From;
CAVA/CBVB = NA/NB
CAVANB= CBVBNA
Therefore;
VB= CAVANB/CBNA
Substituting values;
VB= 2 × 18 ×1 / 0.01×1
VB= 3.60 ml
Therefore; 3.60 ml of base was used.
Answer:
For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.
Explanation:
Answer: is the limiting reagent, 180 g of water is produced
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 2 moles of
Thus 5 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 2 moles of
Thus 5 moles of give = of
Mass of
Thus 180 g of will be produced from the given masses of both reactants.
There are four. Fe, H, C, and O