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Art [367]
2 years ago
8

1 gram of sugar costs 5400 how much would 1 ton cost?

Mathematics
1 answer:
nydimaria [60]2 years ago
7 0

Answer:

5400000000

Step-by-step explanation:

1gram=5400

1kg=5400*1000 (1kg=1000gm)

=5400000

1quntal=5400000*100 (1quntal=100kg)

=540000000

1ton=540000000*10 (1ton=10 quntal)

=5400000000

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What is the approximate result of taking 588,000 from 1.3 million?
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I think the answer to your question is  587.998
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3 years ago
6x+2=-8+3x+25 whats the answer to x?
Nitella [24]

Answer:

x = 5

Step-by-step explanation:

To find the value of x make sure to get it on one side

First subtract 3x from each side. This makes the equation now

3x + 2 = -8 + 25

Now see what 25 subtract by 8 is (17)

3x + 2 = 17

Next subtract 2 from both sides

3x = 15

Lastly, divide 15 by 3, making x equal 5

x = 5

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3 years ago
I need to know how to do the answer and why that’s the anwer
Pavel [41]
Ok so the answer is
4 {x}^{2}

so we multiply numbers that have the same variable

2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\
multiply 2 x 2

2 \times 2 = 4
then multiply the exponents

x ^{3} \times x ^{ - 1}
multipling like this will look like addition.
{x}^{3} \times {x}^{ - 1} = {x}^{2}
so in other words you could do it like this too
{x}^{3} + {x}^{ - 1} = {x}^{2}
now add the exponent with 4
4 + {x}^{2} = 4x ^{2}

now for the last part
{y}^{3} + {y}^{ - 3} = 0
because -3 and 3 added together make 0
0 + 4 {x}^{2} = 4 {x}^{2}
I hope this help(it looks complicated but it's very easy and I hope I helped you out)
6 0
3 years ago
When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in i
Westkost [7]

Answer:

(1) 256 inches

(2) 5 feet

(3) 400 inches

(4) 10 feet

Step-by-step explanation:

(1) The function that gives the height in inches of the spray of water at a distance <em>x</em> from the sprinkler head is given as follows;

h(x) = 160·x - 16·x²

At x = 2 feet, we have;

h(2) = 160 × 2 - 16 × 2² = 256

Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches

(2) The x-coordinate, x_{max}, of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;

x_{max} = -b/(2·a)

The x-coordinate, x_{max}, of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;

x_{max} = -160/(2 × (-16)) = 5

Therefore, the number of feet along the way, the function will reach maximum height, x_{max} = 5 feet

(3) The function, h(x) = 160·x - 16·x², will reach maximum height, h_{max}, at x = 5, therefore;

h_{max} =  h(5) = 160 × 5 - 16 × 5² = 400

The maximum height of the spray, h_{max} = 400 inches

(4) The water is at ground level where h(x) = 0, therefore;

At ground level, h(x) = 0 = 160·x - 16·x²

160·x - 16·x² = 0

∴ 16·x × (10 - x) = 0

By zero product rule, we 16·x = 0, or (10 - x)  = 0, from which we have;

x = 0, or x = 10

The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.

7 0
3 years ago
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