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2 years ago

Please help i don’t understand

Mathematics

1 answer:

34kurt2 years ago

4 0

Answer:

Step-by-step explanation:

First of, let's make a table for y = cos(x)

(x , y): (0 , 1) (π/2 , 0) (π , -1) (3π/2 , 0) (2π , 1)

Now, making a table for y = 2cos(x) is simple. We just have to multiply all the y-values from the previous table by 2.

(x , y): (0 , 2) (π/2 , 0) (π , -2) (3π/2 , 0) (2π , 2)

Graphing these coordinates, we find that the answer is D.

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12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$

This probability is:

$P = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002$

$P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458$

$P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460$

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0

3 years ago

A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the grou

kotykmax [81]

Answer:

(a) The probability that his height is less than 66 inches is 0.2743.

(b) The probability that the height is between 66 and 71 inches is 0.4679.

Step-by-step explanation:

The data given in the question is:

Mean (μ) = 68.4

Standard Deviation (σ) = 4

Let X denote the height of men. We will use the normal distribution z-score formula to calculate the z-score and then look up the probability in the normal probability distribution table. The z-score formula is:

z = (X - μ)/σ

(a) For P(X<66), first calculate the z value.

z = (66-68.4)/4

z = -0.6 (Look up this value in the standard normal distribution table)

P(z<-0.6) = 0.2743

The probability that his height is less than 66 inches is 0.2743.

(b) P(66<X<71) = P(X<71) - P(X<66)

We need to find P(X<71) so, calculating the z-value:

z = (71-68.4)/4

z = 0.65

P(z<0.65) = 0.7422

P(66<X<71) = 0.7422 - 0.2743

P(66<X<71) = 0.4679

The probability that the height is between 66 and 71 inches is 0.4679.

(c) To find the probability P(X>71), we need to find P(X<71) and then subtract it from 1 because the normal distribution table gives values for P(X<k). We have already calculated the value of P(X<71) in part (b) so,

P(X>71) = 1 - P(X<71)

= 1 - 0.7422

P(X>71) = 0.2578

The probability that the height is more than 71 inches is 0.2578.

3 0

3 years ago

Describe the steps you would use to solve the equation<br> 2(4x - 5) + 11 = -63.

goblinko [34]

If u use the app photomath it will give u answer with the steps too

6 0

3 years ago

Read 2 more answers

Solve this!

Reptile [31]

Withdraw- remove
Deposit- put
Discount- take off

5 0

2 years ago

Which is not a solution m-8≤2

Charra [1.4K]

The answer is e because all of the other answers are less than or equal to 2. Hope this helps.

5 0

3 years ago