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2 years ago

Please help i don’t understand

Mathematics

1 answer:

34kurt2 years ago

4 0

Answer:

Step-by-step explanation:

First of, let's make a table for y = cos(x)

(x , y): (0 , 1) (π/2 , 0) (π , -1) (3π/2 , 0) (2π , 1)

Now, making a table for y = 2cos(x) is simple. We just have to multiply all the y-values from the previous table by 2.

(x , y): (0 , 2) (π/2 , 0) (π , -2) (3π/2 , 0) (2π , 2)

Graphing these coordinates, we find that the answer is D.

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How do you find the area of a triangle?

kirza4 [7]

Hello!

We use formulas to find the areas of different shapes. The formula for the area of a triangle is:

1/2 bh

These means that you must multiply the base by the height and then divide it by two.

Good Day!

4 0

3 years ago

Electronics store received a shipment of 20 graphing calculators including eight that are defective four of the calculators are

lisov135 [29]

Answer: If it is probability, there is a 40% chance that a school will receive a defective calculator if the selections are random.

If the calculators are tested and sorted, there can be 3 selections of 4 calculators sent to schools once the 8 defective ones are removed.

Step-by-step explanation: The question is unclear. Is it about subtracting the bad ones and dividing the good ones? Or is it about Taking chances with the selection of calculators to be sent?

If they subtract: 20-8= 12 left 12÷4= 3 sets of good ones.

If they take chances 8/20 = .4 so there is a 40% chance that a bad calculator will be included in the selection.

4 0

3 years ago

Which of the following equations does not represent a true statement

Vanyuwa [196]

Answer:

C) -6-(-3)=3

Step-by-step explanation:

-6-(-3)=

-6+3=

-3 (Not positive 3)

So the third one is incorrect

5 0

3 years ago

Read 2 more answers

Write a cosine function that has an amplitude of 5, a midline of 2 and a period of \frac{2\pi}{5} 5 2π .

vlabodo [156]

Answer:

f(x) = 5*cos(5*x) + 2

Step-by-step explanation:

A general cosine function is written as:

f(x) = A*cos(ω*x) + M

where:

A is the amplitude

M is the midline

ω is the angular frequency.

In this case we know that:

The amplitude is 5, then A = 5

The midline is 2, then M = 2

The period is 2*pi/5

The relation between the angular frequency ω and the period T is:

ω = 2*pi/T

Then if the period is T = 2*pi/5, replacing that in the above equation we find that:

ω = 2*pi/T = 2*pi/(2*pi/5) = 5

ω = 5

Then the function is:

f(x) = 5*cos(5*x) + 2

7 0

3 years ago

I cannot solve this for nothing

Bas_tet [7]

You can multiply the top equation by 3 and the bottom equation by 2, so you get:

-6y = 42
+6y = 18

(You also multiply whatever is in front but it's cut off so...)

Then you can add the equations so you get:

(whatever numbers cut off are) = 60

Then you solve for the variable cut off and sub it into one of the equations and solve for y.

7 0

4 years ago