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3 years ago

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28. The IUPAC name for OH is

1 answer:

Jet001 [13]3 years ago

5 0

Answer:

A

Explanation:

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The atomic mass of magnesium is the weighted average of the atomic masses of

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Answer:

2. All the naturally occurring isotopes of Mg.

Explanation:

You want to know the atomic mass of the magnesium you use in the lab. That’s “natural” magnesium. So, you must use the weighted average of all the naturally occurring isotopes in natural Mg.

1. and 3. are <em>wrong</em>. You won’t get the correct mass for natural Mg if you use only the artificial isotopes for your calculation.

4. is <em>wrong</em>. You must use all the naturally occurring isotopes. The two most abundant isotopes of Mg account for only 90 % of the atoms. If you ignore the other 10 %, your calculation will be wrong.

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3 years ago

When the products of a reaction are hotter than the reactants:

kobusy [5.1K]

A.) The reaction is Exothermic

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3 years ago

In an exothermic reaction:_________ A. The surroundings absorb heat from the reaction mixture. B. The surroundings release heat

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Answer: option A. The surroundings absorb heat from the reaction mixture

Explanation:

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4 years ago

HELP PLZ WHAT IS TRUE ABOUT A LIQUID BUT NOT a gas

Artyom0805 [142]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

A solution of sodium hydroxide is standardized against potassium hydrogen phthalate (KHP, formula weight 204.2 g/mol). From the

enyata [817]

<u>Answer:</u> The molarity of NaOH solution is 0.273 M.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of KHP = 1.794 g

Molar mass of KHP = 204.2 g/mol

Putting values in above equation, we get:

$\text{Moles of KHP}=\frac{1.794g}{204.2g/mol}=0.0088mol$

The chemical reaction for the reaction of KHP and NaOH follows

$KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.0088 moles of KHP will react with = $\frac{1}{1}\times 0.0088=0.0088mol$ of NaOH

To calculate the molarity of NaOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of NaOH = 0.0088 moles

Volume of solution = [32.47 - 0.23] mL = 32.24 mL = 0.03224 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$\text{Molarity of NaOH }=\frac{0.0088mol}{0.03224L}=0.273M$

Hence, the molarity of NaOH solution is 0.273 M.

3 0

3 years ago