Answer:
Synthesis
Explanation:
A sysnthesis reaction takes two or more reactants to create one product
Answer:
The density will be 1.48 g/ mL.
Explanation:
D is the answer! I know it!
Answer:
pH = 9.475
Explanation:
Hello there!
In this case, according to the basic ionization of the hydroxylamine:
The resulting equilibrium expression would be:
![Kb=\frac{[HONH_3^+][OH^-]}{[HONH_2]} =1.1x10^{-8}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BHONH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BHONH_2%5D%7D%20%3D1.1x10%5E%7B-8%7D)
Thus, we first need to compute the initial concentration of this base by considering its molar mass (33.03 g/mol):
![[HONH_2]_0=\frac{1.34g/(33.03g/mol)}{0.500L} =0.0811M](https://tex.z-dn.net/?f=%5BHONH_2%5D_0%3D%5Cfrac%7B1.34g%2F%2833.03g%2Fmol%29%7D%7B0.500L%7D%20%3D0.0811M)
Now, we introduce 
as the reaction extent which provides the concentration of the hydroxyl ions to subsequently compute the pOH:
However, since Kb<<<<1, it is possible to solve for by easily neglecting it on the bottom to obtain:
![x=[OH^-]=\sqrt{1.1x10^{-8}*0.0811}= 2.99x10^{-5}](https://tex.z-dn.net/?f=x%3D%5BOH%5E-%5D%3D%5Csqrt%7B1.1x10%5E%7B-8%7D%2A0.0811%7D%3D%202.99x10%5E%7B-5%7D)
Thus, the pOH is:
And the pH:
Regards!
Answer:
a) 0.88 M, b) 0.88 M, c) 1.93 M, d) 1.6 M
Explanation:
a) Molarity = number moles/L solution = 3.5 mol/ 4 L = 0.875mol/L ≈ 0.88 M
b) 3400 mL = 3.4L
Molarity = number moles/L solution = 4.8 mol/ 3.4 L ≈ 1.4 mol/L = 0.88 M
c) 30.9 g * 1 mol/40 g = 30.9/40 mol
400 mL = 0.4 L
Molarity = number moles/L solution = (30.9/40) mol/ 0.4 L ≈ 1.93 mol/L =
= 1.93 M
d) 340 g * 1 mol/105.99 g = 340/105.99 mol
Molarity = number moles/L solution = (340/105.99) mol/ 2L ≈ 1.6 mol/L =
= 1.6 M
