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laila [671]
3 years ago
7

Why is it important to control the reaction rate of the chemical process

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
8 0
Mg+2HCl=MgCl_2+H_{2(g)}

The reaction creates dihydrogen, hence if it's uncontrolled it could lead to potentially dangerous amounts of gas being released at once.
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What can a emerald be described as
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3 years ago
Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
AnnZ [28]

<u>Answer:</u> The limiting reagent is oxygen gas.

<u>Explanation:</u>

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For propane:</u>

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol

  • <u>For oxygen:</u>

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol

The chemical equation for the combustion of propane follows:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = \frac{1}{5}\times 2.34=0.468mol of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

3 0
3 years ago
Next the students measured the density of aluminum metal. The accepted density for aluminum is 2.7 g/cm3. The students collected
katovenus [111]

Answer:

yo that's too long you should try and my it shorter

3 0
4 years ago
How many hydrogen atoms are in the compound represented by the following bond-line drawing?<br> ОН
Ganezh [65]

Answer:

Theres no drawing

Explanation:

Show drawing

4 0
3 years ago
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