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OverLord2011 [107]
3 years ago
12

​I have a few questions from my homework and I was wondering if I can get some help ​

Chemistry
1 answer:
sashaice [31]3 years ago
3 0
Well it breaks down into small parts
You might be interested in
How do we seperate a mixture of water and sugar
Firlakuza [10]

Answer:

The easiest way to separate a mixture of sugar and water is to use <em><u>distillation</u></em>, a process that separates substances based on their different boiling points. 《☆☆☆☆☆》

Explanation:

Hope it helps JOIN 《Æ §QŮÅĐ》

3 0
3 years ago
What is the percent composition of nitrogen in a 2.57 g sample of Al(NO3)3?
Lisa [10]

Answer:

19.8% of Nitrogen

Explanation:

In the Al(NO₃)₃ there are:

1 atom of Al

3 atoms of N

And 9 atoms of O

The molar mass of Al(NO₃)₃ is:

1 Al * (26.98g/mol) = 26.98g/mol

3 N * (14g/mol) = 42g/mol

9 O * (16g/mol) = 144g/mol

26.98 + 42 + 144 = 212.98g/mol

We can do a conversion using these molar masses to find the mass of nitrogen is the sample, that is:

2.57g * (42g/mol / 212.98g/mol) =

0.51g N

Percent composition of nitrogen is:

0.51g N / 2.57g * 100

= 19.8% of Nitrogen

6 0
2 years ago
3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.
kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

Percent by mass=\frac{mass of solute}{mass of solution} *100

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

  • mass of solute: 3.55 g
  • mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

Percentbymass=\frac{3.55}{91.55}*100

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0
3 years ago
CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol
Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

Learn more about Concentration here:

brainly.com/question/17206790

#SPJ4

3 0
2 years ago
The hot dogs you ate at the barbecue last week were 75% fat-free by weight, had 275 calories, and weighed 110 g. a) What percent
vovangra [49]

Answer:

a) 25%

b) 27.5 g

c) 90%

Explanation:

a) 75% fat-free by weight means 25% of the weight is made by fat.

b) 110 g ___ 100%

      x    ___ 25%

          x = 27.5g

Each hot dog has 27.5g of fat.

c) 9 cal ___ 1 g fat

      y    ___ 27.5 g fat

          y = 247.5 cal

275 cal ___ 100%

247.5 cal ___ z

     z = 90%

90 % of the calories come from fat.

6 0
3 years ago
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