Answer:

Explanation:
Assume that the volume of the stock solution is 1 L.
1. Mass of stock solution

2.Mass of NH₃

3. Moles of NH₃

4. Molar concentration of stock solution

5. Volume of stock needed for dilution
Now that you know the concentration of the stock solution, you can use the dilution formula .

to calculate the volume of stock solution.
Data:
c₁ = 14.89 mol·L⁻¹; V₁ = ?
c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL
Calculations:

PV = nRT
P = 157 kPa = 157 × 10³ Pa
V = 265 ml = 0.265 l
T = 20°C = 293 K
m = 0.479 g
PV•M = mRT
M = (mRT)/(PV)
M = 0.479 g × 8.314 kPa.l/(mol.K) × 293 K / (157 kPa × 0.265 l)
M ≈ 28.04579 g/mol.
Hence, the Molar Mass of Dinitrogen or Nitrogen Gas is 28 g.
Answer:
A
Explanation:
CH4+O2-CO2+ H20
that mean methane has burn in oxygen to produce CO2
#1
<span>The rate of diffusion of a gas is inversely proportional to the square root of its molecular weight.
#2
shape, molecular weight. I don't know for sure though
#3
</span>O2, N2, Ar, H2O vapor