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3 years ago

Rock candy is made from crystallized sugar. What is crystallization?

Physics

2 answers:

malfutka [58]3 years ago

8 0

Answer: The Process Of Forming Crystals

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Looked up on the Internet web.

Explanation: ()

ankoles [38]3 years ago

7 0

Answer: Rock candy is candy made of large sugar crystals. To make rock candy, a supersaturated solution of sugar in water is created and left undisturbed for a few days. The driving force behind crystallization is supersaturation.

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The combustion of 1.631 g of sucrose, C12H22O11(s) , in a bomb calorimeter with a heat capacity of 5.30 kJ/°C results in an incr

VLD [36.1K]

Answer:

= - 26.31 kJ

Explanation:

we know that number of moles is calculated as

$Moles of C_{12}H_{22}O_{11} = \frac{mass}{molecular\ weight}$

$= \frac{(1.631 g)}{(342.29 g/mol)}$

= 0.00476 mol

Heat absorbed by calorimeter $= heat\ capacity \times temperature\ rise$

$= 5.30 kJ/°C x (27.75 - 22.68)°C$

= 26.87 kJ

Enthalpy of combustion

$\Delta Hc = \frac{- 26.87}{0.00486}$

= - 55290.12 kJ/mol

Negative sign shows that the heat is released

The balanced reaction

$C_{12}H_{22} O_{11}(s) + 12 O_2(g) = 12 CO_2(g) + 11 H_2O(l)$

ΔHc = ΔU + Δng (RT)

-55290.12 = ΔU + (12 - 12) *(RT)

$\Delta U = - 55290.12 kJ/mol \times 0.00476 mol$

= - 26.31 kJ

3 0

3 years ago

Can someone please help me with science.

vichka [17]

1 is b because a runs 20 and b rus 102 is c

5 0

3 years ago

In which instrument of the following the water works as a bulb

Montano1993 [528]

Answer:

hydrometer

Explanation:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.

3 0

3 years ago

A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.12 g coins stacked over the 24.2 cm mark, th

pashok25 [27]

Answer:

The mass of the meter stick is $1.66054054054g$

Explanation:

Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero

Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at $50.0cm$

Now lets consider the later case where stick is balanced by two 5.12 g coins .

Here torque due to two coins = $t_{c} = 5.12\times(27.8-24.2)\times2\times9.8$

Torque due to weight of meter stick = $t_{m}$ = $m\times(50-27.8)\times9.8$

where m = mass of the meter stick

Here $t_{c} = t_{m}$ .

Upon equating we will be getting mass of the meter stick = $1.66054054054g$

4 0

3 years ago

A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car

Kisachek [45]

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

$PE = mgh$