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3 years ago

Every time your cats paw hits her toy string, it swings away from her. How does this demonstrate Newton’s third law of motion?

Physics

1 answer:

Wittaler [7]3 years ago

7 0

Answer:

This demonstrates Newton's Third Law because for every action there is an equal and opposite force.

Explanation:

The cat's paw hitting her toy string would be an action therefore when is swings to and from her it it creating and equal and opposite force. In other words, the cat hits it and when the string comes back to her it's coming back the same force just opposite of the direction she hit.

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A 150.0-kg crate rests in the bed of a truck that slows from 50.0 km/h to a stop in 12.0 s. The coefficient of static friction b

Leokris [45]

By Newton's second law,

• the net force acting vertically on the crate is 0, and

∑ F = n - mg = 0 ==> n = mg = 1470 N

where n is the magnitude of the normal force; and

• the net force acting in the horizontal direction on the crate is also 0, with

∑ F = f - b = 0 ==> b = f = µn = 0.645 (1470 N) = 948.15 N

where b is the magnitude of the braking force, f is (the maximum) static friction, and µ is the coefficient of static friction. This is to say that static friction has a maximum magnitude of 948.15 N. If the brakes apply a larger force than this, then the crate will begin to slide.

Note that we are taking the direction of the truck's motion as it slows down to be the positive horizontal direction. The brakes apply a force in the negative direction to slow down the truck-crate system, and static friction keeps the crate from sliding off the truck bed so that the frictional force points in the positive direction.

Let a be the acceleration felt by the crate due to either the brakes or friction. Use Newton's second law again to solve for a :

f = ma ==> a = (948.15 N) / (150.0 kg) = 6.321 m/s²

With this acceleration, the truck will come to a stop after time t such that

0 = 50.0 km/h - (6.321 m/s²) t ==> t ≈ (13.9 m/s) / (6.321 m/s²) ≈ 2.197 s

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3 years ago

Two asteroids in outer space collide, and stick together. The mass of each asteroid, and the velocity of each asteroid before th

zepelin [54]

Answer:

Use the momentum principle

Explanation:

If two asteroids in outer space collide, and stick together and the mass of each asteroid, and the velocity of each asteroid before the impact, are known then the approach that will be useful in analysing this collision is using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of momentum of the bodies after collision. The bodies moves with the same velocity after collision

Let m1 and m2 be the masses of the asteroid

u1 and u2 be their velocity before collision

v be their common velocity

Since momentum = mass × velocity

The relationship that can be used to analyse the approach is;

m1u1 + m2u2 = (m1+m2)v

Note that even though the collision is elastic, the law of conservation will still be used. As a matter of fact this approach can be used if the collision is either elastic or inelastic.

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