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Makovka662 [10]
2 years ago
14

Explain why a luminous flame of a Bunsen burner produces bright yellow light​

Chemistry
2 answers:
rjkz [21]2 years ago
5 0

Answer:

is due to small soot particles in the flame which are heated to incandescence or the shortage of combustion air .

telo118 [61]2 years ago
4 0

Answer:

because of the small soot particles

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Illegal Explosives. Illegal explosives associated with the fireworks season are inherently dangerous because of their composition and unpredictability. Homemade explosives can pose a particular risk for injury because the people making them often lack knowledge and experience in manufacturing fireworks.

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3 years ago
Explain the process of groundwater
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Answer:

Limestone is easily eroded from above and below.

Explanation:

The Florida bedrock is largely made of limestone. Because limestone is a rock that is easily eroded, the landscape of a great part of Florida is classified as karstic.

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3 years ago
HELP ASAP!
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8 0
3 years ago
At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---> +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
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