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solmaris [256]
3 years ago
11

Balance _Na+_H2O->_NaOH_H2

Chemistry
2 answers:
EleoNora [17]3 years ago
5 0

2Na + 2H20 -> 2NaOH + H2

DaniilM [7]3 years ago
3 0

Answer:

2Na + 2H₂O ⟶ 2NaOH + H₂

Step-by-step explanation:

<em>Step 1.</em> Pick the most complicated-looking formula (NaOH).

Put a 1 in front of it.

Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 2</em>: Balance Na.

We have fixed 1 Na on the right. We need 1 Na on the left.

Put a 1 in front of Na.

1Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 3</em>. Balance O.

We have fixed 1 O on the right. We need 1 O on the left.

Put a 1 in front of H₂O.

1Na + 1H₂O ⟶ 1NaOH + H₂

==============

<em>Step 4.</em> Balance H.

We have fixed 2 H on the left and 1 H on the right.

We have 2 H on the left and 3 H on the right. We need one more H (½ H₂) on the left.

Oops! Fractional coefficients! We must multiply all coefficients by a number to give integer coefficients.

===============

<em>Step 5</em>. Get rid of fractions.

Multiply all coefficients by2.

2Na + 2H₂O ⟶ 2NaOH + H₂

We have fixed 4 H on the left and 2H on the right, but we have another 2 H in the H₂.

H is balanced.

===============

<em>Step 6</em>. Write the balanced equation.

2Na + 2H₂O ⟶ 2NaOH + H₂

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Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is 0.5 \frac{moles}{L}

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

In this case:

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So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

moles=\frac{3.744 grams*1mole}{148.3 grams}

moles= 0.025

Then you have:

  • number of moles=0.025
  • volume= 50 mL= 0.05 L (being 1,000 mL= 1 L)

Replacing in the definition of molarity:

molarity=\frac{0.025 moles}{0.05 L}

you get:

molarity=0.5 \frac{moles}{L}

<u><em>The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is </em></u>0.5 \frac{moles}{L}<u><em></em></u>

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