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3 years ago

Balance _Na+_H2O->_NaOH_H2

Chemistry

2 answers:

EleoNora [17]3 years ago

5 0

2Na + 2H20 -> 2NaOH + H2

DaniilM [7]3 years ago

3 0

Answer:

2Na + 2H₂O ⟶ 2NaOH + H₂

Step-by-step explanation:

<em>Step 1.</em> Pick the most complicated-looking formula (NaOH).

Put a 1 in front of it.

Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 2</em>: Balance Na.

We have fixed 1 Na on the right. We need 1 Na on the left.

Put a 1 in front of Na.

1Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 3</em>. Balance O.

We have fixed 1 O on the right. We need 1 O on the left.

Put a 1 in front of H₂O.

1Na + 1H₂O ⟶ 1NaOH + H₂

==============

<em>Step 4.</em> Balance H.

We have fixed 2 H on the left and 1 H on the right.

We have 2 H on the left and 3 H on the right. We need one more H (½ H₂) on the left.

Oops! Fractional coefficients! We must multiply all coefficients by a number to give integer coefficients.

===============

<em>Step 5</em>. Get rid of fractions.

Multiply all coefficients by2.

2Na + 2H₂O ⟶ 2NaOH + H₂

We have fixed 4 H on the left and 2H on the right, but we have another 2 H in the H₂.

H is balanced.

===============

<em>Step 6</em>. Write the balanced equation.

2Na + 2H₂O ⟶ 2NaOH + H₂

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Using the VSEPR theory , what would the representation mean A central atom with 2 connected atoms atom with I lone pair of Jone

VLD [36.1K]

Answer:

The molecule has a bent geometry

Explanation:

Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.

Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.

The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.

3 0

3 years ago

Fritz-Haber process

maks197457 [2]

Answer:

5×10⁵ L of ammonia (NH3)

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the balanced equation above, we can say that:

3 L of H2 reacted to produce 2 L of NH3.

Finally, we shall determine the volume of ammonia (NH3) produced by the reaction of 7.5×10⁵ L of H2. This can be obtained as illustrated below:

From the balanced equation above,

3 L of H2 reacted to produce 2 L of NH3.

Therefore, 7.5×10⁵ L of H2 will react to produce = (7.5×10⁵ × 2)/3 = 5×10⁵ L of NH3.

Thus, 5×10⁵ L of ammonia (NH3) is produced from the reaction.

6 0

3 years ago

What is released in the process of an atom moving from an excited level to a lower energy level? (2 points) a photon an electron

Tcecarenko [31]

An electron is the correct answer

3 0

3 years ago

the value of ksp for pbcl2 is 1.6. what is the lowest concentration of Cl- that would be needed to begin precipitation of PbCl2

deff fn [24]

Answer:

The minimum concentration of Cl⁻ that produces precipitation is 12.6M

Explanation:

The Ksp of PbCl₂ is expressed as:

PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq)

The Ksp is:

Ksp = 1.6 = [Pb²⁺] [Cl⁻]²

When Ksp = [Pb²⁺] [Cl⁻]² the solution begind precipiration.

A 0.010M Pb(NO₃)₂ is 0.010M Pb²⁺, thus:

1.6 = [0.010M] [Cl⁻]²

160 = [Cl⁻]²

12.6M = [Cl⁻]

<h3>The minimum concentration of Cl⁻ that produces precipitation is 12.6M</h3>

7 0

2 years ago

A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?

Anni [7]

Answer:

Explanation:

The mass of the ball can be found by using the formula

$m = \frac{2k}{ {v}^{2} } \\$

v is the velocity

k is the kinetic energy

From the question we have

$m = \frac{2(3.10)}{ {6.70}^{2} } = \frac{6.20}{44.89} \\ = 0.138115...$

We have the final answer as

Hope this helps you

7 0

3 years ago