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solmaris [256]
2 years ago
11

Balance _Na+_H2O->_NaOH_H2

Chemistry
2 answers:
EleoNora [17]2 years ago
5 0

2Na + 2H20 -> 2NaOH + H2

DaniilM [7]2 years ago
3 0

Answer:

2Na + 2H₂O ⟶ 2NaOH + H₂

Step-by-step explanation:

<em>Step 1.</em> Pick the most complicated-looking formula (NaOH).

Put a 1 in front of it.

Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 2</em>: Balance Na.

We have fixed 1 Na on the right. We need 1 Na on the left.

Put a 1 in front of Na.

1Na + H₂O ⟶ 1NaOH + H₂

===============

<em>Step 3</em>. Balance O.

We have fixed 1 O on the right. We need 1 O on the left.

Put a 1 in front of H₂O.

1Na + 1H₂O ⟶ 1NaOH + H₂

==============

<em>Step 4.</em> Balance H.

We have fixed 2 H on the left and 1 H on the right.

We have 2 H on the left and 3 H on the right. We need one more H (½ H₂) on the left.

Oops! Fractional coefficients! We must multiply all coefficients by a number to give integer coefficients.

===============

<em>Step 5</em>. Get rid of fractions.

Multiply all coefficients by2.

2Na + 2H₂O ⟶ 2NaOH + H₂

We have fixed 4 H on the left and 2H on the right, but we have another 2 H in the H₂.

H is balanced.

===============

<em>Step 6</em>. Write the balanced equation.

2Na + 2H₂O ⟶ 2NaOH + H₂

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What is an acid and also what is a base​
expeople1 [14]

Answer:

An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond.

Hope it helps!!!

3 0
2 years ago
Aluminum is often used in the structure of light-weight bicycle frames. How many
Brilliant_brown [7]

Answer:

The first thing that you need to do here is to figure out the mass of the sample.

To do that, you can use its volume and the fact that aluminium is said to have a density of

2.702 g cm

−

3

, which implies that every

1 cm

3

of aluminium has a mass of

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Explanation:

5 0
2 years ago
PLEASE HELP!!!!!!!!! 20 points! Which would be best categorized as heat transfer by convection? Usuing a heat blanket to get war
Ghella [55]
I'd say the correct answer is: Noodles rising and falling apart in boiling water.
3 0
3 years ago
Read 2 more answers
An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.
Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 7°C - 84°C

ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

28.75211 kj

8 0
3 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
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