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3 years ago

Which oxide(s) of manganese have a mass percent of the metal that is greater than 50%?MnO MnO2 Mn2O3All of these102

Chemistry

1 answer:

Hunter-Best [27]3 years ago

5 0

Answer:

All of these

Explanation:

In MnO:

mass of Mn = 55 g (as 1 mole of Mn weighs 55 g)

mass of O = 16 g (as 1 mole of O weighs 16 g)

The mass percent of metal Mn= $\frac{55}{55+16}\times100=\frac{55}{71}\times100=77.46$

In MnO2:

mass of Mn = 55 g

mass of O = 2*16 = 32 g

The mass percent of metal Mn= $\frac{55}{87}\times100=63.22$

In Mn2O3:

mass of Mn = 2*55 = 110 g

mass of O = 3*16 = 48 g

The mass percent of metal Mn= $\frac{110}{158}\times100=69.62$

In all the cases the mass percent of metal is greater than 50.

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2 years ago

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$m(\text{Hg}) = m(\text{residure})$
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$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
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$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

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