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kiruha [24]
3 years ago
11

Which oxide(s) of manganese have a mass percent of the metal that is greater than 50%?MnO MnO2 Mn2O3All of these102

Chemistry
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

All of these

Explanation:

In MnO:

mass of Mn = 55 g (as 1 mole of Mn weighs 55 g)

mass of O = 16 g    (as 1 mole of O weighs 16 g)

The mass percent of metal Mn= \frac{55}{55+16}\times100=\frac{55}{71}\times100=77.46

In MnO2:

mass of Mn = 55 g

mass of O = 2*16 = 32 g

The mass percent of metal Mn=\frac{55}{87}\times100=63.22

In Mn2O3:

mass of Mn = 2*55 = 110 g

mass of O = 3*16 = 48 g

The mass percent of metal Mn=\frac{110}{158}\times100=69.62

In all the cases the mass percent of metal is greater than 50.

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Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1},

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  • T_1 is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

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