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Lilit [14]
3 years ago
7

Can someone please predict the products for these two? Also explain to me how you predicted it, thank you.

Chemistry
1 answer:
balandron [24]3 years ago
6 0
THESE ARE COMBUSTION REACTIONS SO, THE PRODUCT FOR BOTH OF THESE ARE CO2 AND H2O! Here is the balanced reaction equation:
1) C2H2 + 3O2 ➡️ 2CO2 + 2H2O
2) C2H12 + 5O2 ➡️ 2CO2 + 6H2O
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jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

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2 years ago
Fun fact! &lt;3
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4 years ago
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anygoal [31]

Answer: a. Cathode

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In the electrochemical cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.  Thus the electrons are produced at anode and travel towards cathode.

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Thus the overall reaction will be: M+N^{n+}\rghtarrow M^{n+}+N

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