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2 years ago

If B (x,y)=(x-3,y+5), what is B(4,7)? Can anyone help me please

Mathematics

1 answer:

UkoKoshka [18]2 years ago

3 0

Answer:

(B (4, 7 ) = (1, 12 )

Step-by-step explanation:

given

B (x, y ) = (x - 3, y + 5 ) , then

B (4, 7 ) = (4 - 3, 7 + 5 ) = (1, 12 )

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Answer:

Step-by-step explanation:

-2-8/0-2

-10/-2

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3 years ago

On average, 15 minutes elapse between discoveries of fraudulent corporate tax returns in a certain IRS office. What is the proba

Lyrx [107]

Answer:

The probability that more than 30 minutes will elapse before the next fraudulent corporate tax return is discovered=0.1353

Step-by-step explanation:

We are given that

$\beta=15$

We have to find the probability that more that 30 minutes will elapse before the next fraudulent corporate tax return is discovered.

Using exponential distribution

$P(X> x)=e^{-\frac{x}{\beta}}$

The probability that more than 30 minutes will elapse before the next fraudulent corporate tax return is discovered

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$P(x>30)=0.1353$

Hence, the probability that more than 30 minutes will elapse before the next fraudulent corporate tax return is discovered=0.1353

5 0

3 years ago

An initial amount of $2000 is invested in an account at an interest rate of 5% per year, compounded continuously. Find the amoun

yulyashka [42]

Answer:

$2,100.00

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The perimeter of a rectangle 120 feet. The width of the rectangle is equal to one-half the length. Fine the length and width of

yanalaym [24]

Length = 40ft
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3 years ago

Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] $ y =

Advocard [28]

Answer:

The answer is " $\frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}$ ".

Step-by-step explanation:

Given:

$y = e^{{\color{\red}5}\sqrt{x}}$

let

$\to t= 5\sqrt{x}\\\\\frac{dt}{dx}= 5 \frac{1}{2\sqrt{x}}\\\\\frac{dt}{dx}= \frac{5}{2\sqrt{x}}\\\\$

and

$\to y=e^t\\\\\to \frac{dy}{dt}=e^t\\$

$\to \frac{dy}{dt}=e^{5\sqrt{x} }\\$

So,

$\to \frac{dy}{dx}= \frac{dy}{dt} \times \frac{dt}{dx}$

$=e^{5\sqrt{x} }\times \frac{5}{2\sqrt{x}}\\\\= \frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}$

$\to g(x) = 5\sqrt{x} \\\\\to f(x) = e^{(x)}\\\\$

Derivate:

$\to f''g' = \frac{e^{(5\sqrt{x})}5}{(2\sqrt{x})}$

5 0

3 years ago