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lorasvet [3.4K]
2 years ago
11

Use the image to match the arc/angle measure.

Mathematics
1 answer:
IrinaK [193]2 years ago
7 0

Answer:

The following measurements are:

m\angle{STR}=23^\circ (Option #4)

m{QT}=142^\circ (Option #7)

mST=134^\circ (Option #5)

mRQ=38^\circ (Option #2)

Step-by-step explanation:

To begin, we can find the measure of \angle{STR} by applying the inscribed angle theorem: an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

Since the intercepted arc (RS) is 46 degrees, we have:

46=2\theta\\23=\theta

Next, we can find the measure of arc QT using the same theorem. So,

QT=2(71)\\QT=142

Notice that the chord RT is actually a diameter. From the theorem about the inscribed angle including a diameter, we know that the intercepted arc will have a measure of 180^\circ. Since the arc ST is part of the arc RST, and we know RS is 46^\circ, we can set up and solve this equation:

RST = RS + ST\\180 = 46 + ST\\134 = ST

We can use the same idea to find RQ. We know that RQT is 180^\circ and QT is 142^\circ, so:

RQT = RQ + QT\\180 = RQ + 142\\38 = RQ

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andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

                                    = 6 m × 4 m

                                    = 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = \frac{1}{2} \ \pi r^2

                                      $=\frac{1}{2} \times 3 .14 \times 2^2

                                      =6.28

Area of the semi-circle = 6.28 m²

Area of the figure = Area of the rectangle + Area of the semi-circle

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3 years ago
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