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3 years ago

Which is the most common type of precipitation

Chemistry

3 answers:

aliina [53]3 years ago

5 0

Rain is the most common type of precipitation. The conditions for the other types are more rare than those required for rain.

zhannawk [14.2K]3 years ago

5 0

Answer:

The Answer is Rain

Explanation:

Just did It it is correct

salo2 years ago

0 0

RRAAIINN
RAIN :)

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The standard reduction potentials for the Ag+|Ag(s) and Zn2+| Zn(s) half-cell reactions are +0.799 V and -0.762 V, respectively.

mihalych1998 [28]

Answer: The potential of the given cell is 1.551 V

Explanation:

The given chemical cell follows:

$Zn(s)|Zn^{2+}(0.125M)||Ag^{+}(0.240M)|Ag(s)$

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(0.125M)+2e^-;E^o_{Zn^{2+}/Zn}=-0.762V$

Reduction half reaction: $Ag^{+}(0.240M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.799V$ ( × 2)

Net cell reaction: $Zn(s)+2Ag^{+}(0.240M)\rightarrow Zn^{2+}(0.125M)+2Ag(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.799-(-0.762)=1.561V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Ag^{+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = ? V

$E^o_{cell}$ = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=0.125M$

$[Ag^{+}]=0.240M$

Putting values in above equation, we get:

$E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})$

$E_{cell}=1.551V$

Hence, the potential of the given cell is 1.551 V

6 0

4 years ago

The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai

Firdavs [7]

Answer:

A) $N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$ .

B) $Kc=0.0933$ .

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

B) For the calculation of Kc, we rate the equilibrium expression:

$Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}$

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent $x$ , we have:

$[NH_3]=0.6M=2*x$

$x=\frac{0.6M}{2}=0.3M$

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

$[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M$

$[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M$

Therefore, the equilibrium constant is:

$Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933$

C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.

D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

Best regards.

7 0

3 years ago

A blank is a substance that is made by combining two substances

Simora [160]

Do you mean; " A blank is a substance that is made by combining two elements?" (I'm not sure if substances is the right term)

If so then the blank is a compound.

7 0

3 years ago

11. The strength of a force is measured in

dem82 [27]

Answer:

In units.

Explanation:

Such as newtons or pounds.

4 0

3 years ago

The combustion of carbohydrates and the combustion of fats are both exothermic processes, yet the combustion of carbohydrates is

Julli [10]

Explanation:

There are two aspects of a reaction:

Thermodynamics:

Combustion of the compound is reaction with oxygen.

The carbohydrates contain more content of oxygen as compared to fats.

Hence, carbohydrates have lot of oxygen content which are already partially oxidized as compared to fats. Hence, combustion of the carbohydrates is a faster process.

Kinetics:

The molecular reacts also shows that the combustion of the carbohydrates is a faster process.

7 0

4 years ago