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Novay_Z [31]
3 years ago
13

Which is the most common type of precipitation

Chemistry
3 answers:
aliina [53]3 years ago
5 0

Rain is the most common type of precipitation. The conditions for the other types are more rare than those required for rain.

zhannawk [14.2K]3 years ago
5 0

Answer:

The Answer is Rain

Explanation:

Just did It it is correct

salo3 years ago
0 0

RRAAIINN
RAIN :)

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IF 0.5 MOL NITROGEN GAS HAS A VOLUME OF II.0 L SOME TEMPERATURE AND
DENIUS [597]

Answer:

17.92L or 17.92dm³1

Explanation:

number of moles of a gas = volume of that gas/ 22.4(S.V.P)

0.8 mol = x / 22.4

cross multiplication

x = 22.4 × 0.8

x = 17.92

:. the volume of 0.8 mol of nitrogen gas is 17.92dm³ or 17.92L

8 0
3 years ago
True or False: Adding 4.18 joules to water will increase the temperature more than adding 1 calorie to water.
mote1985 [20]

Answer:

Because one calorie is equal to 4.18 J, it takes 4.18 J to raise the temperature of one gram of water by 1°C. In joules, water's specific heat is 4.18 J per gram per °C. If you look at the specific heat graph shown below, you will see that 4.18 is an unusually large value.

6 0
3 years ago
A reading shows a pressure measurement of 43 in. Hg. What is the equivalent pressure in psi? A. 5.73 psi B. 2223.13 psi C. 26.32
oksian1 [2.3K]
43 inHg = 43 inHg*2.54cm/in = 109.22cmHg * 10 mm/cm = 1092.2 mmHg


14.7 psi = 760 mmHg

1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi

Answer: option D. 21.13 psi
7 0
4 years ago
Read 2 more answers
The function of hydrochloric acid in the gastric juice.
irina [24]
The function of hydrochloric acid is to melt the food
5 0
3 years ago
15 POINTS PLEASE HELP What volume of water must be added to 35mL of 2.6m KCl to reduce its concentration to 1.2m? Please explain
BartSMP [9]
First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
5 0
4 years ago
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