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3 years ago

5

Water is continuously changing state and moving from place to place in the water cycle. This diagram shows these processes and m

ovements. (Bro there's no science AHHHH)

1 answer:

sergeinik [125]3 years ago

3 0

Answer: bro- i have no idea wat science that is but heres the water cycle-

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a sample of a gas has a volume kf 640 cm^{3} at 100°c and 1490 mmhg,what would be its volume at stp?

scoundrel [369]

Answer:

V₂ = 918.1 cm³

Explanation:

Given data:

Initial volume = 640 cm³

Initial temperature = 100°C (100+273 = 373 K)

Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)

Final volume = ?

Final temperature = 273 K

Final pressure = 1 atm

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm

V₂ = 342451.2 atm .cm³ . K / 373 K. atm

V₂ = 918.1 cm³

3 0

3 years ago

A solution has a concentration of 0.8 M and contains 15 g AgBrO3. What is the volume of the solution

topjm [15]

Answer:

Solution Concentration: Molarity Moles of solute in one liter of solution Used because it describes how many molecules of solute are in each liter of solution Tro: Chemistry: A Molecular Approach, 2/e 6 amount of solute (in moles) Molarity, M = amount of solution (in L) moles of solute M = L of solution or simply 4

GOOD LUCK!!

3 0

3 years ago

Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of

Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

4 0

2 years ago

Which statements are true concerning our interpretation of the results of an experiment?

miskamm [114]

Answer:

3. Judgement may be affected by what we already think is true (prior knowledge).

Explanation:

This statement is the correct answer because someone could be bias. Due to biases, prior knowledge may be incorrect and our conclusion may be wrong if you don't focus on the data given.

7 0

3 years ago

If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __

natulia [17]

Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

6 0

3 years ago