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2 years ago

Solve the equation and enter the value of x below. -3x-9=-27 x=

Mathematics

2 answers:

kondor19780726 [428]2 years ago

6 0

Answer:

Step-by-step explanation:

-3x=-27+9

-3x=-18

x=-18/-3

x=6

inn [45]2 years ago

4 0

Answer:

$\displaystyle 6 = x$

Step-by-step explanation:

$\displaystyle -3x - 9 = -27 \hookrightarrow \frac{-3x}{-3} = \frac{-18}{-3} \\ \\ x = 6$

I am joyous to assist you at any time.

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If sin theta = 4/5 and theta is in quadrant 2, the value of cot theta is

trasher [3.6K]

Answer:

Cot(theta) = - 0.75 or -3/4

Step-by-step explanation:

The hypotenuse is 5

The y value is 4

We need to find the corresponding x value.

x^2 + y^2 = z^2

X = ?

y = 4

z = 5

x^2 + 4^2 = 5^2

x^2 + 16 = 25

x^2 = 9

Now in this case, you are in quadrant 2, so the x value is - 3

sqrt(x^2) = sqrt(9)

x = - 3

The cot value is the adjacent (x value) / the opposite ( y ) value

Cot(theta) = -3/4

cot(theta) = -0.75

8 0

2 years ago

Read 2 more answers

The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc

AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

$p \propto \dfrac{1}{d}$

Introducing the constant of proportionality

$p = \dfrac{k}{d}$

If 150 pounds is required for a distance of 10 inches from the object

p=150 pounds
d=10 inches

$150 = \dfrac{k}{10}\\\\k=1500$

Therefore, the relationship between p and d is:

$p = \dfrac{1500}{d}$

When d=3 Inches

$p = \dfrac{1500}{3}\\\implies p=500$ pounds$

The pressure applied when the distance is 3 inches is 500 pounds.

4 0

3 years ago

3(2x + 5)2(x + 6)<br> Can someone help me :)

Mamont248 [21]

Answer:

6x+15>2x+12

6x-2x>12-15

4x>-3

x>-3/4

Step-by-step explanation:

6 0

3 years ago

A resident of Bayport claims to the City Council that the proportion of Westside residents

Kazeer [188]

Answer:

The test statistics is $z = -1.56$

The p-value is $p-value = 0.05938$

Step-by-step explanation:

From the question we are told

The West side sample size is $n_1 = 578$

The number of residents on the West side with income below poverty level is $k = 76$

The East side sample size $n_2=688$

The number of residents on the East side with income below poverty level is $u = 112$

The null hypothesis is $H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 < p_2$

Generally the sample proportion of West side is

$\^{p} _1 = \frac{k}{n_1}$

=> $\^{p} _1 = \frac{76}{578}$

=> $\^{p} _1 = 0.1315$

Generally the sample proportion of West side is

$\^{p} _2 = \frac{u}{n_2}$

=> $\^{p} _2 = \frac{112}{688}$

=> $\^{p} _2 = 0.1628$

Generally the pooled sample proportion is mathematically represented as

$p = \frac{k + u}{ n_1 + n_2 }$

=> $p = \frac{76 + 112}{ 578 + 688 }$

=> $p =0.1485$

Generally the test statistics is mathematically represented as

$z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }$

=> $z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }$

=> $z = -1.56$

Generally the p-value is mathematically represented as

$p-value = P(z < -1.56 )$

From z-table

$P(z < -1.56 ) = 0.05938$

$p-value = 0.05938$

3 0

3 years ago

What is the volume of a sphere with a diameter of 9 in.?

a_sh-v [17]

Answer: 121.5 in³

Explanation:

$\textnormal{Volume }= \cfrac{4}{3} \pi (4.5)^3 = 121.5 \pi \ in^3$

6 0

2 years ago

Read 2 more answers