Answer:
Metalloids
Explanation:
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Answer:
1.44 g
Explanation:
From the question given above, the following data were obtained:
Number of mole of HCl = 0.06 mole
Mass of Mg =?
From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,
Number of mole of Mg = number of mole of HCl
Number of mole of Mg = 0.06 mole
Finally, we shall determine the mass of Mg. This can be obtained as follow:
Number of mole of Mg = 0.06 mole
Molar mass of Mg = 24 g/mol
Mass of Mg =?
Mass = mole × molar mass
Mass of Mg = 0.06 × 24
Mass of Mg = 1.44 g
Therefore, the mass of magnesium is 1.44 g
The <span> the Brønsted-Lowry acid donates H⁻.
In this reaction Particle that loose H⁺ is A. NH4⁺ ion.</span>
Well it's definitely an alkaline solution.
Answer:
The enthalpy of the nitrogen-nitrogen bond in N2H4 is 162.6 kJ
Explanation:
For the reaction: N2H4(g)+H2(g)→2NH3(g), the enthalpy change of reaction is
ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4
but we also know that the ΔH rxn is calculated by accounting the sum of number of bonds formed and bonds broken as follows:
ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)
where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed, in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).
Consulting an appropiate reference handbook or table the following values are used:
ΔHºf (NH3) = -46 kJ/mol
ΔHºf (N2H4) = 95.94 kJ/mol
(The enthalpy of fomation of hydrogen in its standard state is zero)
H (N-H) = 391 kJ
H (H-H) = 432 kJ
H (N-N) = ?
So plugging our values:
ΔH rxn = 2mol ( -46.0 kJ/mol) - 1mol(95.4 kJ/mol) = -187.40 kJ
-187.40 kJ = 6(-391 kJ) + 4 (391 kJ) + 432 + H(N-N)
-187.40 kJ = -350 kJ + H(N-N)
H(N-N) = 162.6 kJ
