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xxTIMURxx [149]
2 years ago
11

Simplify 5/9x4 3/5x6 3/11x6/10 and 3 4/5x7 1/2

Mathematics
1 answer:
Sav [38]2 years ago
4 0

Answer:

529/55 and 57/2

Step-by-step explanation:

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Which statement best describes the faces that make up the total surface area of this composite solid? A triangular prism on top
Anestetic [448]

Answer:

The answer is B) 9 faces, 7 rectangles, and 2 triangles

Step-by-step explanation:

I took the test and got it correct

3 0
3 years ago
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If the area of the triangle with vertices (5,2),(x,4) and (0,3) is 25/2, find x?
Evgen [1.6K]

x=7

Pretty Simple..                                                                          h                                                        h                h                                                                                      

5 0
3 years ago
Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94
ra1l [238]
Area for a circle is A= \pi r^2.  We will fill in each area and then solve for the radius.  530.66m^2= \pi r^2 and \frac{530.66m^2}{3.14}=r^2.  ∴169=r^2 and r = 13.  For b, 907.46ft^2= \pi r^2 and \frac{907.46ft^2}{3.14}=r^2.  289=r^2, ∴ r = 17.  For c, 379.94mi^2= \pi r^2, and \frac{379.94mi^2}{3.14}=r^2.  ∴, 121=r^2 and r = 11.  For d, 1962.5cm^2= \pi r^2, and \frac{1962.5cm^2}{3.14}=r^2.  ∴, 625=r^2 so r = 25.  And there you have it!
3 0
3 years ago
Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}

3 0
3 years ago
A -pound bag of Feline Flavor is . An -pound bag of Kitty Kibbles is . Which statement about the unit prices is true?
ser-zykov [4K]

Answer:

Where is the numbers dude? LOL

Step-by-step explanation:

4 0
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