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2 years ago

Hey guys can y’all help quickly?

Physics

1 answer:

Naddik [55]2 years ago

7 0

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

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Question 17 of 25

Oxana [17]

Answer:

I think it is C

Explanation:

states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

3 0

3 years ago

A heterogeneous mixture _____.

defon

Has an uneven distribution of parts throughout the whole mixture

7 0

4 years ago

Read 2 more answers

the term used to measure a change in speed of an object is a. velocity. b. acceleration. c. capacity. d. flow.

Tomtit [17]

The term is acceleration.

(b).

6 0

3 years ago

What is true about colonial families?

MrRissso [65]

Answer:

Explanation:

I just took the test and C was wrong, do not listen to that answer. It is "All of the above"

7 0

3 years ago

Can someone help me?

Leviafan [203]

Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

$V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t$

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

$V_y.t = \frac{2d}{t} .t = 2d$

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0

3 years ago