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2 years ago

Name two elements that are extracted from their compounds by electrolysis.

Chemistry

2 answers:

Paladinen [302]2 years ago

8 0

Answer:

Hydrogen and oxygen

Explanation:

This is the most common compound water

When water goes through electrolysis it produces two elements
H_2 and O_2

The reaction is given by

H_2O-->H_2+O_2

Zanzabum2 years ago

8 0

Answer:

Hydrogen and helium is the answer

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Answer:

3 atoms of carbon

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This is a force that acts over a distance, can not be seen, and causes like poles to repel and opposite poles to attract. What i

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2 years ago

Read 2 more answers

Consider the dissolution of ammonium nitrate. 1.25 g of amminum nitrate is dissolved in enough water to make 25.0 mL of solution

Mrac [35]

Answer:

$\Delta H=-0.02\ kJ$

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

$\Delta H=m\times C\times \Delta T$

Where,

$\Delta H$ is the enthalpy change

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 1.25 g

Specific heat = 4.18 J/g°C

$\Delta T=21.9-25.8\ ^0C=-3.9\ ^0C$

So,

$\Delta H=-1.25\times 4.18\times 3.9\ J=-20.3775\ J$

Negative sign signifies loss of heat.

Also, 1 J = 0.001 kJ

So,

$\Delta H=-0.02\ kJ$

5 0

3 years ago

the individual components of a solution_____.a: can be separated by physical meansb: are chemically combinedc: react to form com

kap26 [50]

I believe the correct response is A. Can be separated by physical means.

4 0

2 years ago

A 25.0 ml sample of 0.150 m butanoic acid is titrated with a 0.150 m naoh solution. what is the ph after 26.0 ml of base is adde

lesantik [10]

First,
Moles of HBu = Volume per liter * moles of HBu/ liter
= 25ml/1000 * 0.15 = 0.00375 moles
moles of NaOH = volume per liter * moles of NaOH/liter
= 1 ml/1000 * 0.15 = 0.00015 moles
according to this equation:
HBu + NaOH → H2O + NaBu
when 1 mol of NaOH gives 1mol of HBu
So 0.00015 of NaOH will give 0.00015 mol of HBu
∴moles of HBu which remains = 0.00375- 0.00015 = 0.0036 moles

∴moles of Bu- produced = 0.00015 moles
when the total volume = 0.025 + 0.026 =0.051 L
[HBu] = 0.0036moles / 0.051 L = 0.071 moles
[Bu] = 0.00015 / 0.051L = 0.0029 moles
when Ka = [H+] [Bu] / [HBu]
1.5x10^-5 = [H+] (0.0029) /(0.071)
∴[H+] =1x10^-6 / 0.076 = 1.5 x 10^-5
∴PH = -㏒[H+]
= - ㏒ 1.5x10^-5
= 4.81

3 0

2 years ago