Answer:
52.2 g
Explanation:
Step 1: Write the balanced equation
3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O
Step 2: Calculate the moles corresponding to 89.7 g of KOH
The molar mass of KOH is 56.11 g/mol.
89.7 g × 1 mol/56.11 g = 1.60 mol
Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH
The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.
Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
0.533 mol × 97.99 g/mol = 52.2 g
Answer:
<em>P1V1</em><em>/</em><em>(</em><em>c1</em><em>+</em><em>2</em><em>3</em><em>7</em><em>)</em><em>=</em><em>P2V2</em><em>/</em><em>(</em><em>c2</em><em>+</em><em>2</em><em>3</em><em>7</em><em>)</em><em> </em><em>where </em><em>c</em><em>=</em><em>Celsius</em>
Explanation:
kelvin scale is alot covinent because of it absolute zero
Answer:
V2= 531.4 ml
Explanation:
T1= 273+45 °C= 318 Kelvin
T2= 273+65 °C= 338 Kelvin
V1= 500ml *( 0.001L/1ml)= 0.5 Liters
V2= 
= 
= 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml
