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Sliva [168]
3 years ago
14

According to Dalton, what happens to atoms during a chemical reaction? Atoms gain or lose energy. Atoms are rearranged. Old atom

s are destroyed. New atoms are created.
Chemistry
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

Atoms are rearranged.

Explanation:

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Explain how you determine molar mass of Ca(No3)2
igor_vitrenko [27]

Answer:

164

1st step we will write desperate molar mass of each element

8 0
3 years ago
An 100g box have a temperature of 22 C. What temperature must a 200g box be kept at in order for both to have the same amount of
Elis [28]

Answer:

the answer is 1 sir BC i t is BC it is BC its 2

4 0
3 years ago
Write the equation for the neutralization reaction in which barium chloride is the salt formed. Show the reaction in which the f
frutty [35]

Answer:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

Explanation:

In a complete neutralization reaction, an acid reacts with a base to form neutral salt and water. To form barium chloride, hydrochloric acid (acid) reacts with barium hydroxide  (base). The balanced chemical equation is:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

8 0
3 years ago
How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significa
satela [25.4K]
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
                                                                           = 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g

7 0
3 years ago
Read 2 more answers
Why bond angle of H2O is maximum then OF2??
Nataly_w [17]
It's lone a little distinction (103 degrees versus 104 degrees in water), and I trust the standard rationalization is that since F is more electronegative than H, the electrons in the O-F bond invest more energy far from the O (and near the F) than the electrons in the O-H bond. That moves the powerful focal point of the unpleasant constrain between the bonding sets far from the O, and thus far from each other. So the shock between the bonding sets is marginally less, while the repugnance between the solitary matches on the O is the same - the outcome is the edge between the bonds is somewhat less.
8 0
3 years ago
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