0. 85 kg of lead, specific heat 128 J/kgC, is heated from 50 C to 95 C. How much heat energy did the sample absorb?
1 answer:
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Answer:
0.82 MPa
Explanation:
the change in pressure 'σ'=160kPa
K= σ/∈ => σ/3∈
K= 160/(3 x 0.065)
K=820 kPA=0.82 MPa
Thus,the bulk modulus of the tissue 'K' is 0.82 MPa