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aleksklad [387]
2 years ago
5

0. 85 kg of lead, specific heat 128 J/kgC, is heated from 50 C to 95 C. How much heat energy did the sample absorb?

Physics
1 answer:
Zanzabum2 years ago
5 0
4896

0.85 x 45 x 128 = 4896

Change in energy = specific heat capacity x mass x change in temperature
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emmainna [20.7K]

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3 years ago
An car has an acceleration of 8.0 m/s/s. How much time is needed to reach a velocity of 30 m/s from
polet [3.4K]

Answer:

3.75s

Explanation:

a = 8.0 m/s V = 30 m/s U = 0 m/s t = ?

t = V - U/a

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5 0
3 years ago
You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the
Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed ,\omega=\frac{v}{r}

Using the formula

\omega=\frac{0.49}{0.27}=1.8 rad/s

\omega=\frac{2\pi}{T}

T=\frac{2\pi}{\omega}

Time period,T=\frac{2\pi}{1.8}=3.49 s

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed,V_{max}=0.49 m/s

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5 0
3 years ago
Read 2 more answers
Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.
gogolik [260]

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

r=\frac {GM}{v^{2}}

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

3 0
3 years ago
The percentage of radioactive atoms that decay during one (1) half-life ____________.
Rina8888 [55]

Answer:

is the same

Explanation:

Half life is define as the time it take for fifty percentage of a radioactive material to disintegrate. After the first half-life passes, half (fifty percentage) of the remaining radioactive material will disintegrate in the next half-life. Then, half of that amount in turn disintegrate in the following half-life and the halving continues.

4 0
3 years ago
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