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3 years ago

The percentage of radioactive atoms that decay during one (1) half-life ____________.

Physics

2 answers:

Rina8888 [55]3 years ago

4 0

Answer:

is the same

Explanation:

Half life is define as the time it take for fifty percentage of a radioactive material to disintegrate. After the first half-life passes, half (fifty percentage) of the remaining radioactive material will disintegrate in the next half-life. Then, half of that amount in turn disintegrate in the following half-life and the halving continues.

laiz [17]3 years ago

3 0

Answer:50% of its starting atomic mass

Explanation:

The radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. The half life is the time taken for the activity of a given amount of a radioactive substance to decay to half of its starting mass.

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3 years ago

An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa

Natali [406]

Answer:

1.38*10^18 kg

Explanation:

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where:

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ma= mass of the astronaut

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3 years ago

The resistance and the magnitude of the current depend on the path that the current takes. The drawing shows three situations in

maria [59]

Answer: (a). Resistance = 0.4286ohms and Current (I) = 7A

(b). Resistance (R) = 0.027 ohms and Current (I) = 111.1A

(c). Resistance (R) = 0.1071 ohms and Current (I) = 28A

Explanation:

From the question, given that;

ρ = 1.5*10-2ῼ.m

Lo = 7cm = 0.07m

V = 3V

From the formula R = ρL/A, where A is the area of cross section, L is the length of material and ρ is the resistivity.

(A)

L = 4Lo and A = 2Lo*Lo

R = ρL/A

R = ρ4Lo/(2Lo*Lo)

R = 2ρ /Lo = 2*1.5*10-2/0.07

R = 0.4286 ῼ

From this the current becomes;

I = V/R = 3/ 0.4286 = 6.99 = 7A

(B)

L = Lo and A = 4Lo * 2Lo

R = ρL/A

R = ρLo/ (4Lo*2Lo) after eliminating Lo from both sides we get,

R = ρ/8Lo = 1.5*10-2 / 8*0.07

R = 0.027

Current (I) = V/R = 3/0.027 = 111.1A

(C)

L = 2Lo and A = Lo * 4Lo

R = ρL/A

R = ρ2Lo/ (Lo*4Lo) eliminating Lo from both sides we get,

R = ρ/2Lo = 1.5*10-2 / 2*0.07 = 0.1071

The current becomes;

I = V/R = 3/0.1071 = 28A

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faust18 [17]

Its B i got it right on the test

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