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2 years ago

Hi ..I really need help on this one

Mathematics

1 answer:

IgorLugansk [536]2 years ago

5 0

Answer:

LCM of 3 and 2 is 6

so, firstly we had to make the denominator same:-

$\frac{2(2a + 1) + 3(3a - 1)} {6}$

$\frac{4a + 2 + 9a - 3}{6}$

$\frac{13a - 1}{6}$

Step-by-step explanation:

hope this helps you!!!

XxITSCHOCOLOVERxX

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Out of 50 basketball players trying to make a team, 5 will be chosen. 36 of the 50 are seniors and the remaining players are jun

AveGali [126]

Answer: 5503680

Step-by-step explanation:

The coach wants 2 senior out of 36 so he have

C₃₆,₂ = 36!/( 36 - 2 )! = 36*35*34!/34! = 36 * 35 = 1260

possibilities

Now he also wants 3 juniors out of 14

C₁₄,₃ = 14!/ (14- 3)! = 14*13*12*11!/11! = 14*13*12 = 2184

Now for each pair of senior (from 1260 outcomes) coach has 2184 possiblities therefore

Coach has

2184 * 1260 = 2751840 possibilities to choose from

Again as there are 2 senior to choose for captain we have to multiply by 2 to get the total ways the team could be

2751840*2 = 5503680

6 0

3 years ago

Someone please help me understand how to do this

andrey2020 [161]

Answer: These are the answers for the first section

A) 1/5(10)-4= -2

B) 1/5(-15)-4= -7

C) 1/5(2)-4= -3.6

Step-by-step explanation: You plug in those numbers for X

8 0

3 years ago

I need help with this question

Feliz [49]

Answer:

B = 5 and F = 5

Step-by-step explanation:

Step 1: B = 5 because 350(5) = 1750

Step 2: F = 5 because 525(5) = 2625

Step 3: 2625 + 1750 = 4375

8 0

3 years ago

I need an accurate answer please

kotykmax [81]

x = –6

Solution:

Given expression is $\sqrt[3]{x-2}+5=3$ .

Step 1: Isolate the radical by subtracting 5 from both sides of the equation.

$\Rightarrow\sqrt[3]{x-2}+5-5=3-5$

$\Rightarrow\sqrt[3]{x-2}=-2$

Step 2: Cube both sides of the equation to remove the cube root.

$\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3$

Cube and cube root get canceled in left side of the equation.

$\Rightarrow\ x-2=-8$

Step 3: To solve for x.

Add 2 on both sides of the equation.

$\Rightarrow\ x-2+2=-8+2$

$\Rightarrow\ x=-6$

Hence the solution is x = –6.

6 0

3 years ago

Rectangle ABCD with coordinates A(1,1), B(4,1), C(4,2) and D(1,2) dilates with respect to the origin to give rectangle A’B’C’D’.

Delvig [45]

Answer: Option C.

Step-by-step explanation:

You need to find the distance AB with the formula for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then, substituting the coordinates of the points A(1,1) and B(4,1), you get:

$AB=\sqrt{(4-1)^2+(1-1)^2}=3$

You know that A'B'=6, then the scale factor of dilation can be calculated with:

$k=\frac{A'B'}{AB}$

Substituting values, you get:

$k=\frac{6}{3}\\\\k=2$

This matches with the option C.

8 0

3 years ago

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Hi ..I really need help on this one ​

Hi ..I really need help on this one