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QveST [7]
3 years ago
9

Two pistons are in an enclosed volume with fluid in between them, such that

Physics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

The pressure in the fluid just below Piston 1 is

p_1=F_1/A_1=361\text{ Pa}.p

1

​

=F

1

​

/A

1

​

=361 Pa.

The pressure in the fluid just below Piston 2 is the same according to Pascal's law:

p_2=p_1=361\text{ Pa}.p

2

​

=p

1

​

=361 Pa.

The force being exerted on Piston 2 to keep the two pistons in equilibrium is

F_2=p_2A_2=330\text{ N}.F

2

​

=p

2

​

A

2

​

=330 N.

Explanation:

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Explanation:

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