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QveST [7]
3 years ago
9

Two pistons are in an enclosed volume with fluid in between them, such that

Physics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

The pressure in the fluid just below Piston 1 is

p_1=F_1/A_1=361\text{ Pa}.p

1

​

=F

1

​

/A

1

​

=361 Pa.

The pressure in the fluid just below Piston 2 is the same according to Pascal's law:

p_2=p_1=361\text{ Pa}.p

2

​

=p

1

​

=361 Pa.

The force being exerted on Piston 2 to keep the two pistons in equilibrium is

F_2=p_2A_2=330\text{ N}.F

2

​

=p

2

​

A

2

​

=330 N.

Explanation:

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Using a radar gun, you emit radar waves at a frequency of 6.2 GHz that bounce off of a moving tennis ball and recombine with the
Keith_Richards [23]

Answer:

23.4 m/s

Explanation:

f = actual frequency of the wave = 6.2 x 10⁹ Hz

f_{app} = frequency observed as the ball approach the radar

f_{rec} = frequency observed as the ball recede away from the radar

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frequency observed as the ball approach the radar is given as

f_{app}=\frac{f(V+v)}{V}                                 eq-1

frequency observed as the ball recede the radar is given as

f_{rec}=\frac{f(V-v)}{V}                                  eq-2

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Using eq-2 and eq-1

B = \frac{f(V+v)}{V}- \frac{f(V-v)}{V}

inserting the values

969 = \frac{(6.2\times 10^{9})((3\times 10^{8})+v)}{(3\times 10^{8})}- \frac{(6.2\times 10^{9})((3\times 10^{8})-v)}{(3\times 10^{8})}

v = 23.4 m/s

8 0
3 years ago
Como calcular massa volume e densidade?
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Piensa así M
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Answer:

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