Answer:
No
Step-by-step explanation:
13 + (-36) means you are adding 13 more to -36 which is -23 whereas 13 +36 is 39.
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
1. 32
2. 45
3.84
yea that how you do it
the line would be at x=15 and you would shade all to the left of the line and a point in that zone or on the line would work in the equation
Answer:
Volume of a cone: V = (1/3)πr2h.Step-by-step explanation: