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Harman [31]
3 years ago
7

What is tan M? Will give brainliest!!!! Please help ASAP

Mathematics
2 answers:
Len [333]3 years ago
8 0
Tan angle = opposite leg/ adjacent leg = 24/45
Answer is D.
yuradex [85]3 years ago
4 0
Tan M = opposite/adjacent = 24/45

Answer: D
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How do you write negative 4 tenths as a fraction?
jasenka [17]

Answer:

-4/10

Step-by-step explanation:

6 0
3 years ago
A line has a slope of 3 and a y-intercept of 5. What is its equation in slope-intercept form? Write your answer using integers,
s344n2d4d5 [400]

Answer:

y=3x+5

Step-by-step explanation:

The problem is asking for slope-intercept form, luckily, they gave us both of those things.

Slope-intercept form: y=mx+b, where m= slope and b= y-intercept.

So,

y=3x+5

Hope this helps!

7 0
3 years ago
Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-
Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

ax^2+bx+c=0

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}

In this case, the exercise gives you this Quadratic equation:

5x^2 + 3x - 4 = 0

You can identify that the numerical coefficients are:

a=5\\\\b=3\\\\c= - 4

Therefore, you can substitute values into the Quadratic formula shown above:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0
3 years ago
Read 2 more answers
Which angle is complimentary to 3?
MA_775_DIABLO [31]

Answer:

non of yhrm

Step-by-step explanation:

8 0
2 years ago
Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
stiv31 [10]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• <u>Radius</u> = 5 units

• <u>Centre </u> = (0,0)

<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

  • Here we can see that the distance of point from centre is less than the radius.

<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>

5 0
2 years ago
Read 2 more answers
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