Answer:
-4/10
Step-by-step explanation:
Answer:

Step-by-step explanation:
The problem is asking for slope-intercept form, luckily, they gave us both of those things.
Slope-intercept form:
, where
slope and
y-intercept.
So,

Hope this helps!
Answer: FIRST OPTION
Step-by-step explanation:
<h3>
The missing picture is attached.</h3>
By definition, given a Quadratic equation in the form:

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.
The Quadratic Formula is the following:

In this case, the exercise gives you this Quadratic equation:

You can identify that the numerical coefficients are:

Therefore, you can substitute values into the Quadratic formula shown above:

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.
Answer:
non of yhrm
Step-by-step explanation:
Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• <u>Radius</u> = 5 units
• <u>Centre </u> = (0,0)
<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>
- Here we can see that the distance of point from centre is less than the radius.
<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>