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DochEvi [55]
3 years ago
7

What is the molarity of a solution in which 25g NaCl in a 2.00 L solution?

Chemistry
1 answer:
Paladinen [302]3 years ago
5 0

Mass of sodium :- 23 grams

Mass of Chlorine :- 35.5 grams

Mass of NaCl :- 58.5 grams

mass given :- 25 grams

moles :- 0.432 ( given mass/ ionic mass)

molarity =   \frac{moles}{vol}  \\ molarity =  \frac{0.432}{2}  \\ molarity = 0.216 \: mole{l}^{ - 1} or \: molar

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In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of
Likurg_2 [28]
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

3 0
3 years ago
Read 2 more answers
Can anyone help me? thank you :))
Alex_Xolod [135]
8. 63360
9. 1000
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6 0
3 years ago
While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

5 0
3 years ago
How many moles of h2o will be produced from 42.0 grams of h2o2
lisabon 2012 [21]

The answer is 44.6 mol


5 0
3 years ago
Read 2 more answers
4. Identify the different parts to this word problem. A bowling ball of 35.2kg, generates 218 kg.m/s units of momentum. What is
Dafna1 [17]

<u>Given:</u>

Mass of the ball = 35.2 kg

Momentum =  218 kg m/s

<u>To determine:</u>

The velocity of the ball

<u>Explanation:</u>

Momentum (p) of an object is the product of its mass  (m) and velocity (v)

p = m*v

v = p/m = 218 kg.ms-1/35.2 kg = 6.19 m/s

Ans: The velocity of the ball is 6.19 m/s

3 0
3 years ago
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