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valentinak56 [21]
3 years ago
9

For a single H2 molecule, H2 → 2H, the dissociation energy is 4.52 eV. How much energy would have to be put in (in kJ) to dissoc

iate a mole of hydrogen molecules?
Chemistry
1 answer:
grandymaker [24]3 years ago
6 0

Answer: 7.2418 x 10^-19 joules

Explanation:

1 eV equals 1.602 x 10^-19 joules

Then 4.52eV will be multiplied by the above value to give 7.2418 x 10^-19 joules which is the energy required to dissociate the hydrogen molecule

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We let x be the pressure of each product at equilibrium, giving this ICE table:
                                           2NO2 (g) ↔ 2NO (g) + O2 (g)
     Initial pressure (atm):    0.500            0               0
     Change (atm):               -2x                +2x           +x
     Equilibrium (atm):          0.500-2x       2x             x

We can calculate x from Kp:
     Kp = [NO]^2 [O2] / [NO2]^26.5x10^-6 = (2x)^2 (x) / (0.500-2x)^2

Approximating that 2x is negligible compared to 0.500 simplifies the equation to 
     6.5x10^-6 = (2x)^2 (x)/(0.500)^2 = 4x^3 / (0.500)^2

Then we solve for x:
     x3 = (6.5x10^-6)(0.500)^2 / 4
     x = 0.00741

The pressure of NO2 at equilibrium is therefore 
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