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valentinak56 [21]
3 years ago
9

For a single H2 molecule, H2 → 2H, the dissociation energy is 4.52 eV. How much energy would have to be put in (in kJ) to dissoc

iate a mole of hydrogen molecules?
Chemistry
1 answer:
grandymaker [24]3 years ago
6 0

Answer: 7.2418 x 10^-19 joules

Explanation:

1 eV equals 1.602 x 10^-19 joules

Then 4.52eV will be multiplied by the above value to give 7.2418 x 10^-19 joules which is the energy required to dissociate the hydrogen molecule

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Although both nitrogen (N) and phosphorous (P) belongs to the same series there are several properties which are different between both the element. The number of electrons present in nitrogen is seven which are present in the -s and -p orbitals. The electronic configuration of nitrogen is 1s²2s²2p³. In which the outermost electrons are the valence electrons i.e. 5 valence electrons are present. The maximum orbitals are possible under the principal quantum number 2 are -s and -p orbitals. Now the maximum capacity of the p orbital to contain 6 electrons, as it is half filled in nitrogen another 3 electrons can be incorporated. Thus the maximum number of electrons can be present in nitrogen is 10 among which 8 is the valence electrons.

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