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ELEN [110]
3 years ago
11

Match the correct properties and characteristics of each type of rock?

Chemistry
2 answers:
Over [174]3 years ago
6 0

Sedimentary- deposition of material on Earth's surface or in bodies of water/ made of hard layers formed under high temperature and pressure

Igneous- cooled magma/ has a shiny surface throughout

Metamorphic- made of layers that are weathered relatively easily/ arises from transformation of existing rocks

Lelu [443]3 years ago
5 0
Sedimentary -<span>deposition of material on Earth’s surface or in bodies of water
</span><span>igneous- </span><span>cooled magma
</span>metamorphic-<span>made of hard layers formed under high temperature and pressure</span>
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C). How many mole of oxygen would be produced from reacting 7 mole of HgO (mercury (II) oxide)?
Leni [432]

Answer:

There will be produced 3.5 moles of oxygen (O2)

Explanation:

Step 1: Data given

Number of moles Mercury (II) oxide (HgO) = 7 moles

Step 2: The balanced equation

2HgO → O2 + 2Hg

Step 3: Calculate number of moles of O2

For 2 moles of Mercury (II) oxide (HgO) we produce 1 mol of O2 and 2 moles of Hg

For 7 moles of Mercury (II) oxide (HgO) we'll have 7/2 = 3.5 moles of O2

There will be produced 3.5 moles of oxygen (O2)

3 0
4 years ago
1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase
Natalka [10]

<u>Given</u> :

  • Amount = 20 kg
  • Heat energy absorbed = 237,000 J
  • Temperature change = 15 °C

<u>Formula applied</u> :

\boxed {Q = mc \triangle T}

  • Q = absorbed heat
  • m = mass
  • c = specific heat capacity
  • ΔT = temperature change

Let's solve for c !

⇒ 237,000 = 20 × c × 15

⇒ c = 237,000 ÷ 300

⇒ \boxed {c = 790 J kg^{-1} K^{-1}}

∴ The specific heat capacity of granite is <u>790 J kg⁻¹ K⁻¹</u>.

5 0
2 years ago
How did John dalton describe atoms?
mamaluj [8]

Answer:

John Dalton described the atoms based on there chemical and physical properties of which some were disproved later.

Explanation:

John Dalton described the atoms as

  1. Atoms are the smallest indivisible particles of matter.
  2. Atoms can neither be created nor destroyed.
  3. All atoms of the same element are identical by mass and size.
  4. Atoms of the different element have different mass and size.
  5. Atoms combined to form a compound and they do so in simply whole number ratio.
4 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
The star betelgeuse is 325 light years away. If it were to explode in a supernova tonight, would we know? Explain your answer.
Dahasolnce [82]

Answer:

We will not know immediately

Explanation:

The distance of star Betelgeuse = 325 light years

Therefore, if it where to explode, at the location, we would have a supernovae such that the luminosity of the star multiplies several multiple times

However, due to the distance of Betelgeuse from the Earth, it will take the light of the explosion, 325 years to reach Earth and the explosion as it happens will not be noticed here on Earth immediately

6 0
3 years ago
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