Interval notation
(-infinity sign, 1)
Set-builder notation
{x|x less than equal to 1}
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
Answer:
1 and 1/6
Step-by-step explanation:
To rename a fraction you multiply both numbers by however many times the original denominator goes into the new one.
2 goes into 6 three times.
1 times 3 is 3
and 2 times 3 is 6
so 1/2=3/6
3 goes into 6 twice
2 times 2 is 4
and 2 times 3 is 6
so 2/3=4/6
to add fractions you add the numerators while keeping the denominators the same.
3+4=7 so:
3/6+4/6=7/6
6/6=1
so 7/6 contains 1 whole
once you take that out you have 1/6 left over
Answer:
Step-by-step explanation:
we know that
The formula to calculate the area for a trapezoid is equal to
where
a and b are the parallel bases
h is the height of trapezoid
A is the area
<em>Solve for a</em>
That means ----> isolate the variable a
Multiply by 2 both sides to remove the fraction in the right side
Divide by h both sides
Subtract b both sides
Rewrite
