3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0

1 answer:

3 0

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially, the density of this unknown meta is mathematically given as

D= 0.23 g/ml

<h3>What is the density of this unknown metal if the final reading from the graduate cylinder was 65.0 mL?</h3>

Generally, the equation for the Volume of water is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

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