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mario62 [17]
2 years ago
14

3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0

Chemistry
1 answer:
Olenka [21]2 years ago
3 0

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

<h3>What is the density of this unknown metal if the final reading from the graduate cylinder was 65.0 mL?</h3>

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

Read more about mass

brainly.com/question/15959704

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A lithium flame has a characteristic red color due to emissions of wavelength 671 nm. What is the mass equivalence of 1 mol of p
e-lub [12.9K]

Answer:

1.98x10⁻¹² kg

Explanation:

The <em>energy of a photon</em> is given by:

  • E= hc/λ

h is Planck's constant, 6.626x10⁻³⁴ J·s

c is the speed of light, 3x10⁸ m/s

and λ is the wavelenght, 671 nm (or 6.71x10⁻⁷m)

  • E = 6.626x10⁻³⁴ J·s * 3x10⁸ m/s ÷ 6.71x10⁻⁷m = 2.96x10⁻¹⁹ J

Now we multiply that value by <em>Avogadro's number</em>, to <u>calculate the energy of 1 mol of such protons</u>:

  • 1 mol =  6.023x10²³ photons
  • 2.96x10⁻¹⁹ J *  6.023x10²³ = 1.78x10⁵ J

Finally we <u>calculate the mass equivalence</u> using the equation:

  • E=m*c²
  • m=E/c²
  • m =  1.78x10⁵ J / (3x10⁸ m/s)² = 1.98x10⁻¹² kg

6 0
3 years ago
Metals can be highly purified using electrolysis. Which equation best reflects the overall process of purifying copper?
makvit [3.9K]

Answer:

A. Cu^+2(aq)cathode ---> Cu^+2(aq)anode

Explanation:

Electrolysis is the process in which current is passed through a solution thereby causing a chemical change at the anode and cathode. Copper is being purified using electrolysis by using impure copper at the anode and pure copper at the cathode. This pure and impure copper are placed in a copper(ii)sulfate electrolyte solution and dc current is made to pass through it.  The resulting changes at the anode and cathode are given by the equation:

cathode: Cu²⁺  + 2e⁻    ⇒     Cu

anode:    Cu     ⇒       Cu²⁺  + 2e⁻

3 0
3 years ago
Read 2 more answers
Identify the substances in this reaction:
lukranit [14]

Answer:

is an aqueous reactant

is a liquid product

is a gaseous product

Explanation:

H_2CO_3 ⇔ CO_2 + H_2O

Hydrogen carbonate dissocates to form carbon dioxide and water. The acid (hydrogen carbonate) is in aqueous form and it dissociates to water (liquid) and carbon dioxide (a gas). It is also seen that the hydrogen carbonate is on the reactant side and it dissociates to produce water and carbon dioxide.

WH_2CO_3<u> is an aqueous reactant</u> (a reactant undergoes changes in a chemical reaction

<u />H_2O<u> is a liquid product</u> (product refers to the species produced from  chemical reaction)

<u />CO_2<u> is a gaseous product</u>

6 0
3 years ago
What did rutherford learn about the atom from his gold-foil experiment?
cluponka [151]
Hi there!

Rutherford's experiment showed that the atom's nucleus <em>did </em>have a positive charge. The α particles' trajectory was altered when it went through the gold foil, which, in turn resulted in the discovery of the atom's positive charge.

I hope this helps!
Brady
4 0
3 years ago
Chlorine (cl) has an atomic number of 17. it often forms an ion by gaining 1 electron. what would its charge be?
Aliun [14]

Answer:

= -1

Explanation:

  • Chlorine belongs to the halogen group in the periodic table. It has an atomic number of 17, which indicates the number of protons and electrons in a neutral atom of chlorine is 17.
  • Therefore; with an atomic number of 17, its electronic configuration will be 2:8:7.
  • Thus; to attain a stable configuration chlorine requires to gain one electron, by so doing it becomes a negatively charged ion with a charge of -1.
6 0
3 years ago
Read 2 more answers
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