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mario62 [17]
2 years ago
14

3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0

Chemistry
1 answer:
Olenka [21]2 years ago
3 0

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

<h3>What is the density of this unknown metal if the final reading from the graduate cylinder was 65.0 mL?</h3>

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

Read more about mass

brainly.com/question/15959704

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2. What ions are present in what ratio in a solution of aqueous calcium chloride?
Alenkasestr [34]

Answer:

\mathrm{Ca}^{2+} \text { and } \mathrm{Cl} \text { - ions are present in } 1: 2 \text { ratio in a solution of aqueous calcium chloride. }

Explanation:

Here in Calcium Chloride ionic bond is present in between calcium and chlorine atoms. As we know according to Octet rule calcium have two excess atoms and for matching nearest noble gas electronic configuration. It donate two electrons to gain more stability and form \mathrm{Ca}^{2+}, while chlorine is deficient from one electron to meet nearest noble gas electronic configuration therefore two chlorine atoms accept excess electron from calcium individually and form two\mathrm{Cl}^{-} ions.

\text { Equation is as follows: } \mathrm{Ca}^{2+}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{CaCl}_{2}

Hence aqueous solution of calcium chloride breaks the ionic bond pairing in one \mathrm{Ca}^{2+}and two\mathrm{Cl}^{-}ions: \mathrm{CaCl}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \quad \mathrm{Ca}^{2+}(\mathrm{ag})+2 \mathrm{Cl}(\mathrm{ag})

5 0
3 years ago
Created from the ...... of ..... in layers over long periods of time
Setler79 [48]
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8 0
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Select all of the following equations that represent an exothermic reaction.
masya89 [10]

Answer:

C(graphite) → C(diamond), ΔH = - 0.45 kcal

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Explanation:

C(graphite) → C(diamond), ΔH = - 0.45 kcal

CH4 + 2O2 → CO2 + 2H2O + 212,800 cal

These reactions are exothermic reaction because heat is evolved.

The energy changes occur during the bonds formation and bonds breaking.

There are two types of reaction endothermic and exothermic reaction.

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

6 0
3 years ago
If you have 35.255 g of pure H2O in a water bottle, how much of that 35.255 g is mass due to Oxygen atoms? (only put a number fo
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Answer:

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Explanation:

35.255 x16/18=31.34  O

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Explanation:

Just did the test and got it right

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