The solution to be tested in this experiment must be buffered to ph of 10. If the ph were considerably higher, such as 12, how w

Question

WARRIOR [948]

2 years ago

6

The solution to be tested in this experiment must be buffered to ph of 10. If the ph were considerably higher, such as 12, how w

ould the [oh-] change

Chemistry

1 answer:

Serhud [2] · Answer 1 · 2023-04-06T05:33:12+03:00

For a solution to be tested in this experiment and must be buffered to pH of 10, the [OH-] change will be, The hydroxide concentration would be higher and the formation of insoluble hydroxide salts with Mg^2 and Ca^2 would cause the determined concentration of water hardness to be too low.

<h3>What would be the [OH-] change?</h3>

Generally, the equation for the Total hardness is mathematically given as

$T=\frac{A*D*1000}{B}$

Where

$D=\frac{molarity}{0.01}$

D=0.02/0.01=2

Therefore

$T=\frac{A*D*1000}{B}\\\\T=\frac{20.4*2*1000}{25}$

T=1632ppm

in conclusion, The hydroxide concentration would be higher .