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WARRIOR [948]
2 years ago
6

The solution to be tested in this experiment must be buffered to ph of 10. If the ph were considerably higher, such as 12, how w

ould the [oh-] change
Chemistry
1 answer:
Serhud [2]2 years ago
5 0

For a solution to be tested in this experiment and must be buffered to pH of 10,  the [OH-] change will be, The hydroxide concentration would be higher and the formation of insoluble hydroxide salts with Mg^2 and Ca^2 would cause the determined concentration of water hardness to be too low.

<h3>What would be the [OH-] change?</h3>

Generally, the equation for the  Total hardness is mathematically given as

T=\frac{A*D*1000}{B}

Where

D=\frac{molarity}{0.01}

D=0.02/0.01=2

Therefore

T=\frac{A*D*1000}{B}\\\\T=\frac{20.4*2*1000}{25}

T=1632ppm

in conclusion, The hydroxide concentration would be higher .

Read more about Concentration

brainly.com/question/16979235

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Answer:

Mass of H₂O is 3.0g

Explanation:

The reaction equation is given as:

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Parameters that are known:

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Unknown: mass of water consumed = ?

Solution

To solve this kind of problem, we simply apply some mole concept relationships.

  • First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:

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Workings

>>>>     Number of moles of CO₂ =?

          Molar mass of CO₂ :

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        Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹

     Number of moles of CO₂ = \frac{7.3}{44} = 0.166moles

>>>>>>   if 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O

>>>>>> Mass of water consumed = number of mole of H₂O x molar mass

             Mass of H₂0 = 0.166 x ?

Molar mass of H₂O:

                 Atomic mass of H = 1g

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 Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹

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