Laura sees a horse pulling a buggy.

The specific heat capacity of a substance is a physical property of matter. It is defined as the amount of heat that is to be supplied to a unit mass of the material to produce a unit change in its temperature.

The SI unit of specific heat is joule per kelvin and kilogram, J/(K kg).

Now,

Specific heat for water is 4.1813 Jg⁻¹K⁻¹.

Latent heat of vaporization of water is 2257 Jg⁻¹.

Energy lost by steam in it's process of conversion to water, is the energy acquired by water resulting in an increase in it's temperature.

$Q = mS \Delta T$

Q= Heat transferred

m= mass of the substance

T= temperature

Also,

$Q = mL$

L= Latent heat of fusion/ vaporization ( during phase change)

Now applying the above equations to the problem:

$m_{w} S_{w} (T-27) = (m_{s} L) + m_{s}S_{w} (100 -T)$

$38.5 \times 4.1813 \times (T-27) = (1.10 \times 2257) + 1.10 \times 4.1813 \times (100 -T)$

Temperature = 44.02°C

8 0

4 years ago

Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round

gladu [14]

Answer:

$atoms \ H= 9.767x10^{24}atoms$

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

$atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms$

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

7 0

3 years ago

When looking at Newman projections are there instances where the staggered confirmation is not the lowest in energy? Explain you

stiks02 [169]

Answer:

let's summarize the caution as we are given with human projection. We have to tell them stances where staggered confirmation is not the lowest in energy. Okay, so let's see that. Are there any instances that which conforms tiger is not the lowest energy. Okay, so the lowest energy is what then happened? The lowest in energy already happens on living. Honestly, when, when it happens the lowest in energy only happens when the bulky groups are at 1 80 degree with each other. When it happens when bulky, bulky, bulky groups are at 1 80 degree. Okay, When they are, for example, when the bulky groups are in this way At 180°, then it is Louis Why? Because repulsion are very less repulsion very less. Got it. So we have to tell when it is not the lowest so far not the lowest instance. These bulky groups should be together. So if they either make of angle of 60° or 300° together, suppose this is a bulky group one and this is a bulky group two and okay, so if it makes a 60 degree or 300 degree then this um have the highest energy Or has the energy is not lowest in it. Why? It is not lowest in it Because at 300° or 60°. Why? Because the pulsations are very high repulsion. Are you ready? Hi. So by looking at the humans projection we can conclude that when the if the bulky group parrot 1, 80 degree be considered as the lowest energy. And if they are at 300 or 60 degree or close to each other, republicans are higher and they are not in lowest energy.

7 0

3 years ago