Explanation:
The given reaction equation will be as follows.
![[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%5Crightleftharpoons%20%5BFe%5E%7B3%2B%7D%5D%20%2B%20%5BSCN%5E%7B-%7D%5D)
Let is assume that at equilibrium the concentrations of given species are as follows.
M
M
M
Now, first calculate the value of
as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
= 
= 
Now, according to the concentration values at the re-established equilibrium the value for
will be calculated as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
M
Thus, we can conclude that the concentration of
in the new equilibrium mixture is
M.
The mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.
<h3>How to calculate mass?</h3>
The mass of an object can be calculated using the following formula:
F = ma
Where;
- F = force (N)
- m = mass (kg)
- a = acceleration (m/s²)
m = F/a
m = 356/4
m = 89kg
Therefore, the mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.
Learn more about mass at: brainly.com/question/19694949
Answer:
Nuclear reaction takes place at the nucleus whereas chemical reaction involves valence electrons
Explanation:
Answer:
The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1
Explanation:
<span> red litmus paper turns </span>blue <span>under basic or alkaline conditions, with the color change occurring over the pH range 4.5–8.3 at 25 °C (77 °F). Neutral litmus paper is purple.</span>