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Viefleur [7K]
2 years ago
12

1. What is the relation between distance and speed?

Chemistry
1 answer:
Inga [223]2 years ago
6 0

Answer:

option no b is right answer

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PLZ HELP! Give me a really (winner) good idea for a kids science fair! My little sister has to do one through my school and I ne
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A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation
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2 years ago
Water acts as a solvent.<br> a. True<br> b. False
Talja [164]
True. Water acts as a solvent as the solute dissolves into water. 
7 0
3 years ago
Hydrogen peroxide is a powerful oxidizing agent; it is used in concentrated solution in rocket fuel and in dilute solution in ha
Anestetic [448]

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Co = 10pd/M

Where;

Co = concentration = ?

p = percent of the hydrogen peroxide =  30%

d = Density of hydrogen peroxide =  1.39 g/ml

M = Molar mass  = 34 g/mol

Substituting values;

Co = 10 × 30 ×  1.39/34

Co = 12.26 M

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Learn more: brainly.com/question/6111443

4 0
2 years ago
if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?
skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Density = mass / volume


The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span>                                                                   = 1246.25 g</span>


Specific heat capacity of water = 4.186 J<span>/ g °C.</span>


Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

      5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
               T = 1.04 °C + 23 °C
               T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.
4 0
3 years ago
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