Question

A bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume of the tire? type in your answer using the correct number of significant figures. use the formula for charles' law: v1 t1 = v2 t2 l

Answer 1

The relationship between the volume, temperature, and pressure of the gas can be given by Charles law. The volume of the tire is 1.1 L.

What is Charle's law?

According to Charles's law, the volume is directly proportional to the temperature of the gas at a constant pressure.

Charle's law can be shown as,

$\rm \dfrac{V_{1}}{T_{1}} = \rm \dfrac{V_{2}}{T_{2}}$

Given,

Initial volume = 1.0 L

Initial temperature = 295 K

Final volume = ?

Final temperature = 325 K

Substituting values in the above equation the final volume can be calculated as:

$\begin{aligned}\rm V_{2} &= \rm \dfrac{V_{1}T_{2}}{T_{1}}\\\\&= \dfrac{ 1 \times 325}{295}\\\\&= 1.1\;\rm L\end{aligned}$

Therefore, the final resulting volume of the tire is 1.1 L.

Learn more about Charle's law here:

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